python重新提取卷曲brakets中的项

我的sql中有一个大型数据集，如：

("Successfully confirmed payment - {'PAYMENTINFO_0_TRANSACTIONTYPE': ['expresscheckout'], 'ACK': ['Success'], 'PAYMENTINFO_0_PAYMENTTYPE': ['instant'], 'PAYMENTINFO_0_RECEIPTID': ['1037-5147-8706-9322'], 'PAYMENTINFO_0_REASONCODE': ['None'], 'SHIPPINGOPTIONISDEFAULT': ['false'], 'INSURANCEOPTIONSELECTED': ['false'], 'CORRELATIONID': ['1917b2c0e5a51'], 'PAYMENTINFO_0_TAXAMT': ['0.00'], 'PAYMENTINFO_0_TRANSACTIONID': ['3U4531424V959583R'], 'PAYMENTINFO_0_ACK': ['Success'], 'PAYMENTINFO_0_PENDINGREASON': ['authorization'], 'PAYMENTINFO_0_AMT': ['245.40'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITY': ['Eligible'], 'PAYMENTINFO_0_ERRORCODE': ['0'], 'TOKEN': ['EC-82295469MY6979044'], 'VERSION': ['95.0'], 'SUCCESSPAGEREDIRECTREQUESTED': ['true'], 'BUILD': ['7507921'], 'PAYMENTINFO_0_CURRENCYCODE': ['GBP'], 'TIMESTAMP': ['2013-08-29T09:15:59Z'], 'PAYMENTINFO_0_SECUREMERCHANTACCOUNTID': ['XFQALBN3EBE8S'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITYTYPE': ['ItemNotReceivedEligible,UnauthorizedPaymentEligible'], 'PAYMENTINFO_0_ORDERTIME': ['2013-08-29T09:15:59Z'], 'PAYMENTINFO_0_PAYMENTSTATUS': ['Pending']}", 1L, datetime.datetime(2013, 8, 29, 11, 15, 59))

我使用下面的正则表达式从花括号内的第一个项目列表中提取数据

paypal_meta_re = re.compile(r"""\{(.*)\}""").findall

这正如预期的那样工作，但是当我试图从字典值中删除方括号时，我得到了一个错误

这是我的密码：

paypal_meta = get_paypal(order_id)
paypal_msg_re = paypal_meta_re(paypal_meta[0])
print type(paypal_msg_re), len(paypal_msg_re)
paypal_str = ''.join(map(str, paypal_msg_re))
print paypal_str, type(paypal_str)
paypal = ast.literal_eval(paypal_str)
paypal_dict = {}
for k, v in paypal.items():
    paypal_dict[k] = str(v[0])
if paypal_dict:
    namespace['payment_gateway'] = { 'paypal' : paypal_dict}

这是回溯：

Traceback (most recent call last):
  File "users.py", line 383, in <module>
    orders = get_orders(user_id, mongo_user_id, address_book_list)
  File "users.py", line 290, in get_orders
    paypal = ast.literal_eval(paypal_str)
  File "/usr/local/Cellar/python/2.7.2/lib/python2.7/ast.py", line 49, in literal_eval
    node_or_string = parse(node_or_string, mode='eval')
  File "/usr/local/Cellar/python/2.7.2/lib/python2.7/ast.py", line 37, in parse
    return compile(source, filename, mode, PyCF_ONLY_AST)
  File "<unknown>", line 1
    'PAYMENTINFO_0_TRANSACTIONTYPE': ['expresscheckout'], 'ACK': ['Success'], 'PAYMENTINFO_0_PAYMENTTYPE': ['instant'], 'PAYMENTINFO_0_RECEIPTID': ['2954-8480-1689-8177'], 'PAYMENTINFO_0_REASONCODE': ['None'], 'SHIPPINGOPTIONISDEFAULT': ['false'], 'INSURANCEOPTIONSELECTED': ['false'], 'CORRELATIONID': ['5f22a1dddd174'], 'PAYMENTINFO_0_TAXAMT': ['0.00'], 'PAYMENTINFO_0_TRANSACTIONID': ['36H74806W7716762Y'], 'PAYMENTINFO_0_ACK': ['Success'], 'PAYMENTINFO_0_PENDINGREASON': ['authorization'], 'PAYMENTINFO_0_AMT': ['86.76'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITY': ['PartiallyEligible'], 'PAYMENTINFO_0_ERRORCODE': ['0'], 'TOKEN': ['EC-6B957889FK3149915'], 'VERSION': ['95.0'], 'SUCCESSPAGEREDIRECTREQUESTED': ['true'], 'BUILD': ['6680107'], 'PAYMENTINFO_0_CURRENCYCODE': ['GBP'], 'TIMESTAMP': ['2013-07-02T13:02:50Z'], 'PAYMENTINFO_0_SECUREMERCHANTACCOUNTID': ['XFQALBN3EBE8S'], 'PAYMENTINFO_0_PROTECTIONELIGIBILITYTYPE': ['ItemNotReceivedEligible'], 'PAYMENTINFO_0_ORDERTIME': ['2013-07-02T13:02:49Z'], 'PAYMENTINFO_0_PAYMENTSTATUS': ['Pending']
                                   ^
SyntaxError: invalid syntax

这是可行的，但我不能使用它，因为返回的一些记录没有拆分，而且不准确

基本上，我希望将花括号中的项目从值中删除方括号，然后从中创建一个新词典。

如果需要包含花括号，代码将忽略以下内容：

r"""({.*})""")

请注意，括号现在位于

{…}

的周围

或者，如果字典前面总是有一条消息和一个破折号，您可以使用

str.partition（）

将其拆分：

paypal_msg = paypal_meta[0].partition(' - ')[-1]

或者使用

str.split（）

将拆分限制为一次：

paypal_msg = paypal_meta[0].split(' - ', 1)[-1]

尽量避免将这样的Python结构放入数据库；将JSON存储在单独的列中，而不是对象的字符串转储中

paypal_msg = paypal_meta[0].split(' - ', 1)[-1]