Python lxml-规范化字典中的所有元素子元素
我试图解析一个安全椭圆XML定义文件,以便自动执行测试 我试图实现的是,对于每个定义,转换字典中的测试标准和标准 标准XML结构如下所示:Python lxml-规范化字典中的所有元素子元素,python,lxml,Python,Lxml,我试图解析一个安全椭圆XML定义文件,以便自动执行测试 我试图实现的是,对于每个定义,转换字典中的测试标准和标准 标准XML结构如下所示: <criteria operator="AND"> <criteria comment="Affected IOSXE configuration" operator="AND"> <criterion comment="ASR 1000 series router" test_ref="o
<criteria operator="AND">
<criteria comment="Affected IOSXE configuration" operator="AND">
<criterion comment="ASR 1000 series router" test_ref="oval:org.cisecurity:tst:5943" />
<criteria comment="Affected IOSXE configuration" operator="OR">
<criteria comment="Zone-based firewall configured" operator="AND">
<criterion comment="Match TCP or UDP" test_ref="oval:org.cisecurity:tst:6071" />
<criterion comment="ZBFW inspection enabled" test_ref="oval:org.cisecurity:tst:5850" />
</criteria>
<criteria comment="NAT and PPTP ALG are enabled" operator="AND">
<criterion comment="NAT configured" test_ref="oval:org.cisecurity:tst:6020" />
<criterion comment="NAT enabled" test_ref="oval:org.cisecurity:tst:6146" />
<criterion comment="PPTP ALG disabled" negate="true" test_ref="oval:org.cisecurity:tst:5668" />
</criteria>
<criteria comment="NAT and TCP reassembly are enabled" operator="AND">
<criterion comment="NAT configured" test_ref="oval:org.cisecurity:tst:6020" />
<criterion comment="NAT enabled" test_ref="oval:org.cisecurity:tst:6146" />
<criterion comment="Affected processor" test_ref="oval:org.cisecurity:tst:5622" />
</criteria>
<criterion comment="EoGRE is enabled" test_ref="oval:org.cisecurity:tst:6003" />
</criteria>
</criteria>
<criterion comment="IOSXE version is affected" test_ref="oval:org.cisecurity:tst:6178" />
</criteria>
这将使用以下结果填充我的字典,显然缺少嵌套的子元素:
{'cisco_adv_id': 'cisco-sa-20131030-asr1000',
'cisco_adv_url': 'http://tools.cisco.com/security/center/content/CiscoSecurityAdvisory/cisco-sa-20131030-asr1000',
'criteria': [[('comment', 'Affected IOSXE configuration'),
('operator', 'AND')],
[('comment', 'IOSXE version is affected'),
('test_ref', 'oval:org.cisecurity:tst:6178')]],
'cve_id': 'CVE-2013-5547',
'oval_id': 'oval:org.cisecurity:def:4321',
'title': 'Cisco IOS XE Software Malformed EoGRE Packet Denial of Service '
'Vulnerability'},
我可以使用getchildren()检查嵌套for循环,并检查元素是否有子元素,但这听起来不是最佳解决方案,因为每个定义都有一个或多个条件/条件元素
关于如何更有效地解析这个问题,有什么想法吗
提前感谢。如果使用递归,则相对容易 对于第一个示例,我尝试保持与您相同的组织:每个条件都是一个包含属性和子项的列表,但都存储为dict而不是tuple
def get_data(el):
if el.tag =='criteria':
data = {'criteria': [el.attrib]}
for desc in el.iterchildren():
data['criteria'].append(get_data(desc))
return data
else:
return {'criterion': el.attrib}
问题是返回的数据不容易使用:每个条件最多可以包含三个DICT(属性、条件或条件),您必须进行一些测试才能知道哪个是哪个。在第二个示例中,您预先知道列表包含什么:如果键是条件,您知道您将有一个条件指令列表
def get_data(el):
if el.tag =='criteria':
data = {}
data.update(el.attrib)
for desc in el.iterchildren():
key = desc.tag
if not key in data:
data[key] = []
data[key].append(get_data(desc))
return data
else:
return el.attrib
谢谢@bobrobbob,iterchildren方法确实让它更容易。
def get_data(el):
if el.tag =='criteria':
data = {}
data.update(el.attrib)
for desc in el.iterchildren():
key = desc.tag
if not key in data:
data[key] = []
data[key].append(get_data(desc))
return data
else:
return el.attrib