在python中，根据另一个子列表中相应的权重对子列表进行排序

我有两个嵌套列表

list1

和

list2

list1

表示我需要排序的值的子列表，根据

list2

中表示

list1

权重的第二个子列表：

list1 = [[0.002, 0.001, 0.002, 0.1, 0.001, 0.2, 0.03, 0.04, 0.002, 0.03, 0.004, 0.0004, 0.005, 0.05],
         [0.007, 0.0001, 0.0002, 0.0001, 0.001, 0.02, 0.0003, 0.007, 0.007, 0.008, 0.0006, 0.0004, 0.005, 0.05],
         [0.0009, 0.000, 0.0002, 0.9, 0.091, 0.2, 0.03, 0.04, 0.002, 0.03, 0.004, 0.0004, 0.005, 0.0009],
         [0.002, 0.001, 0.002, 0.1, 0.001, 0.2, 0.03, 0.04, 0.002, 0.03, 0.004, 0.0004, 0.005, 0.055]]
   


  list2 =[[0.06165411, 0.04111233, 0.06165411, 0.049487340000000005, 0.04111233, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.06165411, 0.04111233, 0.020541780000000003, 0.0, 0.0, 0.049487340000000005], 
          [0.29708409, 0.19810227000000002, 0.049487340000000005, 0.19810227000000002, 0.020541780000000003, 0.09898182000000001, 0.09898182000000001, 0.29708409, 0.29708409, 0.09898182000000001, 0.09898182000000001, 0.0, 0.0, 0.049487340000000005], 
          [0.19810227000000002, 0.09898182000000001, 0.049487340000000005, 0.09898182000000001, 0.09898182000000001, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.0, 0.0, 0.19810227000000002], 
          [0.06165411, 0.04111233, 0.06165411, 0.049487340000000005, 0.04111233, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.06165411, 0.04111233, 0.020541780000000003, 0.0, 0.0, 0.09898182000000001]]

我想根据

list2

中相应的排序子列表对

list1

中的每个子列表进行排序。我编写了以下代码：

def sort_list(list1, list2):
    z = [x for _, x in sorted(zip(list2, list1))]
    return(z)

sort_fea = []
for i in range(len(list1)):
    c1 = list1[i]
    c2 = list2[i]
    sort_fea.append(sort_list(c1, c2))
print('The sorted_list1 =',sort_fea)

我得到了以下正确的结果：

sorted_list1 =[[0.0004, 0.005, 0.004, 0.04, 0.2, 0.001, 0.001, 0.03, 0.03, 0.05, 0.1, 0.002, 0.002, 0.002],
               [0.0004, 0.005, 0.001, 0.0002, 0.05, 0.0003, 0.0006, 0.008, 0.02, 0.0001, 0.0001, 0.007, 0.007, 0.007],
               [0.0004, 0.005, 0.002, 0.004, 0.04, 0.2, 0.03, 0.03, 0.0002, 0.0, 0.091, 0.9, 0.0009, 0.0009],
               [0.0004, 0.005, 0.004, 0.04, 0.2, 0.001, 0.001, 0.03, 0.03, 0.1, 0.002, 0.002, 0.002, 0.055]]

是否有使用

numpy

或任何其他方法的更快的方法

sort_fea = []
for i in range(len(list1)):
    result = [x for _, x in sorted(zip(list2[i], list1[i]))]
    sort_fea.append(result)
print(sort_fea)

输出：

[[0.0004, 0.005, 0.004, 0.04, 0.2, 0.001, 0.001, 0.03, 0.03, 0.05, 0.1, 0.002, 0.002, 0.002],
 [0.0004, 0.005, 0.001, 0.0002, 0.05, 0.0003, 0.0006, 0.008, 0.02, 0.0001, 0.0001, 0.007, 0.007, 0.007],
 [0.0004, 0.005, 0.002, 0.004, 0.04, 0.2, 0.03, 0.03, 0.0002, 0.0, 0.091, 0.9, 0.0009, 0.0009],
 [0.0004, 0.005, 0.004, 0.04, 0.2, 0.001, 0.001, 0.03, 0.03, 0.1, 0.002, 0.002, 0.002, 0.055]]

---

据我所知，这将加快您的代码速度。

也许使用

pandas

的解决方案会更快：

import pandas as pd

list1 = [[0.002, 0.001, 0.002, 0.1, 0.001, 0.2, 0.03, 0.04, 0.002, 0.03, 0.004, 0.0004, 0.005, 0.05],
         [0.007, 0.0001, 0.0002, 0.0001, 0.001, 0.02, 0.0003, 0.007, 0.007, 0.008, 0.0006, 0.0004, 0.005, 0.05],
         [0.0009, 0.000, 0.0002, 0.9, 0.091, 0.2, 0.03, 0.04, 0.002, 0.03, 0.004, 0.0004, 0.005, 0.0009],
         [0.002, 0.001, 0.002, 0.1, 0.001, 0.2, 0.03, 0.04, 0.002, 0.03, 0.004, 0.0004, 0.005, 0.055]]

list2 =[[0.06165411, 0.04111233, 0.06165411, 0.049487340000000005, 0.04111233, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.06165411, 0.04111233, 0.020541780000000003, 0.0, 0.0, 0.049487340000000005],
          [0.29708409, 0.19810227000000002, 0.049487340000000005, 0.19810227000000002, 0.020541780000000003, 0.09898182000000001, 0.09898182000000001, 0.29708409, 0.29708409, 0.09898182000000001, 0.09898182000000001, 0.0, 0.0, 0.049487340000000005],
          [0.19810227000000002, 0.09898182000000001, 0.049487340000000005, 0.09898182000000001, 0.09898182000000001, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.0, 0.0, 0.19810227000000002],
          [0.06165411, 0.04111233, 0.06165411, 0.049487340000000005, 0.04111233, 0.020541780000000003, 0.04111233, 0.020541780000000003, 0.06165411, 0.04111233, 0.020541780000000003, 0.0, 0.0, 0.09898182000000001]]

df = pd.DataFrame({'l1': list1, 'l2': list2}).apply(pd.Series.explode)
out = df.groupby(level=0).apply(lambda x: x.sort_values(['l2', 'l1'])['l1'].values.tolist()).tolist()

print(out)

印刷品：

[[0.0004, 0.005, 0.004, 0.04, 0.2, 0.001, 0.001, 0.03, 0.03, 0.05, 0.1, 0.002, 0.002, 0.002], 
 [0.0004, 0.005, 0.001, 0.0002, 0.05, 0.0003, 0.0006, 0.008, 0.02, 0.0001, 0.0001, 0.007, 0.007, 0.007], 
 [0.0004, 0.005, 0.002, 0.004, 0.04, 0.2, 0.03, 0.03, 0.0002, 0.0, 0.091, 0.9, 0.0009, 0.0009], 
 [0.0004, 0.005, 0.004, 0.04, 0.2, 0.001, 0.001, 0.03, 0.03, 0.1, 0.002, 0.002, 0.002, 0.055]]

---

谢谢你的回答。只有一个问题是，您的代码的结果是连续列表，而我需要的结果是子列表的原始列表，如sort_fea=[，…]，[，…]，[，…]，…]您能看看我新编辑的答案吗？我想，我希望答案能解决你的问题。