内部服务器错误-Python
这是我在Python-Flask中的代码。在这里,我输入剧院(剧院表)的数据,然后获取相应的id,然后将屏幕添加到屏幕表中相应的剧院id 问题是Theatre被添加到数据库中,并且我能够获取id。Screen的代码似乎不起作用(如果我注释掉session.Screen add and commit语句,则for循环起作用) 如果屏幕提交没有发生,甚至回滚也不会发生内部服务器错误-Python,python,flask,sqlalchemy,flask-sqlalchemy,Python,Flask,Sqlalchemy,Flask Sqlalchemy,这是我在Python-Flask中的代码。在这里,我输入剧院(剧院表)的数据,然后获取相应的id,然后将屏幕添加到屏幕表中相应的剧院id 问题是Theatre被添加到数据库中,并且我能够获取id。Screen的代码似乎不起作用(如果我注释掉session.Screen add and commit语句,则for循环起作用) 如果屏幕提交没有发生,甚至回滚也不会发生 session_theatre = Session_theatre() session_screen = Session_scree
session_theatre = Session_theatre()
session_screen = Session_screen()
id = 1
if request.method == "POST":
if form.validate_on_submit():
name = str(form.name.data)
city = str(form.location.data)
address = str(form.address.data)
no_of_screen = int(form.total_no_screen.data)
if (name !="" and name!=" " and city != "" and city != " " and address != ""and address != " " and no_of_screen != None):
t = Theatre(name,city,address,1)
try:
session_theatre.add(t)
session_theatre.commit()
query = session_theatre.query(Theatre).filter_by(name=name,city =city).all()
for i in query :
id = i
for i in range (0,no_of_screen):
flash(id)
screen = Screen(str(i+1),1,20,1,20,id)
session_screen.add(screen)
session_screen.commit()
flash("Successfully added !!")
except :
session_screen.rollback()
session_theatre.rollback()
flash("Oops something went wrong !!")
finally:
session_screen.close()
session_theatre.close()
else :
flash("Please fill the input")
return render_template('admin/add_theatre.html',form = form)
屏幕模型
class Screen(db.Model):
__tablename__ = "screens"
id = db.Column(db.Integer,primary_key=True)
screen_num = db.Column(db.String(1))
seat_row_start = db.Column(db.Integer)
seat_row_end = db.Column(db.Integer)
seat_col_start = db.Column(db.Integer)
seat_col_end = db.Column(db.Integer)
theatre_id = db.Column(db.Integer, db.ForeignKey('theatres.id'))
def __init__(self, screen_num,
seat_row_start,seat_row_end,seat_col_start,seat_col_end,theatre_id):
self.screen_num = screen_num
self.seat_row_start = seat_row_start
self.seat_row_end = seat_row_end
self.seat_col_start = seat_col_start
self.seat_col_end = seat_col_end
self.theatre_id = theatre_id
要从
session\u剧院
的查询中获取列表,必须在末尾添加all()
:
query = session_theatre.query(Theatre).filter_by(name=name,city =city).all()
查询返回剧院
对象的列表,您可以访问每个剧院
对象的id
属性,该属性在列表中迭代并按其名称访问:
for obj in query :
for i in range (0,no_of_screen):
flash(obj.id)
screen = Screen(i+1,1,20,1,20,obj.id)
session_screen.add(screen)
session_screen.commit()
代码没有正确缩进。@doru编辑了代码。。检查代码循环的第二个
没有缩进,它应该缩进。你应该添加屏幕
模型的代码。我可以获取id,但屏幕没有添加到数据库中什么是id
,一个int
或一个列表
?不,它会引发异常@Doru。让我检查一下错误,我已经再次更新了答案。我认为该查询返回一个“剧院”对象列表,您可以通过名称访问每个Theatre
对象的id
属性。