Python 不使用if/else语句的代码

这是我评估的开始。我能提供一些帮助吗？

您的代码有一些缩进问题，而且用户输入的总是str string类型。在检查if语句之前，需要将权重转换为int。您还应该使用num1>15而不使用=，因为您已经在num1中使用了它。我删除了标记类，因为您的代码与itelif无关。num1>15应该是else

print("Select operation.")
print("1.Price of your luggage")
print("2.Exit")


# Take input from the user 
choice = input("Enter choice(1/2:")

if choice == '1':
    num1=(input("Enter wieght of your first  luggage " ))

if num1 <=15:
    print('Your first item is free')

elif num1 >=15:
    print('Your items will cost you money')

elif choice == '2':
    raise SystemExit()

print("Select operation.")
print("1.Price of your luggage")
print("2.Exit")

# Take input from the user 
choice = input("Enter choice(1/2:")
if choice == '1':
    num1 = int(input("Enter wieght of your first  luggage " ))
    if num1 <= 15:
        print('Your first item is free')
    else:
        print('Your items will cost you money')
elif choice == '2': 
    raise SystemExit()

Select operation.
1.Price of your luggage
2.Exit
Enter choice(1/2:1
Enter wieght of your first  luggage 12
Your first item is free