Python多if-else函数并返回

这在python上可能吗

def NearSourceFactor(seismic_source_distance,seismic_source_select): 
    Na = 0 
    if (seismic_source_distance <= 2) and (seismic_source_select == "A"):
        Na == 1.5
    elif (seismic_source_distance <= 5) and (seismic_source_select == "A"):
        return Na == 1.2
    elif (seismic_source_distance > 10) and (seismic_source_select == "A"):
        return Na == 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "B"):
        return Na == 1.3
    elif (seismic_source_distance <= 5) and (seismic_source_select == "B"):
        return Na == 1.0
    elif (seismic_source_distance > 10) and (seismic_source_select == "B"):
        return Na == 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "C"):
        return Na == 1.0
    elif (seismic_source_distance <= 5) and (seismic_source_select == "C"):
        return Na == 1.0
    elif (seismic_source_distance > 10) and (seismic_bldg_geometry == "C"):
        return Na == 1.0

Na = NearSourceFactor(seismic_source_distance,seismic_source_select) 

地震震源为10，地震震源为B，但不幸的是，答案为无

我希望答案是1.0

def NearSourceFactor(seismic_source_distance,seismic_source_select): 

    if (seismic_source_distance <= 2) and (seismic_source_select == "A"):
        return 1.5
    elif (seismic_source_distance <= 5) and (seismic_source_select == "A"):
        return 1.2
    elif (seismic_source_distance > 10) and (seismic_source_select == "A"):
        return 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "B"):
        return 1.3
    elif (seismic_source_distance <= 5) and (seismic_source_select == "B"):
        return 1.0
    elif (seismic_source_distance >= 10) and (seismic_source_select == "B"):
        return 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "C"):
        return 1.0
    elif (seismic_source_distance <= 5) and (seismic_source_select == "C"):
        return 1.0
    elif (seismic_source_distance > 10) and (seismic_bldg_geometry == "C"):
        return 1.0

Na = NearSourceFactor(seismic_source_distance,seismic_source_select) 

我修复了它，因此它可以满足您的要求，但请注意以下事项：

a没有理由配置要返回的变量，例如，只需返回值return 1

b当编写Na==1.0时，实际上是在比较并接收一个布尔值

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c试着看看是否可以将逻辑更改为不包含太多的if station（如果您的默认值为1），这样您就可以将所有内容都放在一个else station中，例如

如果地震震源为10，则所有条件都不匹配。你期望它做什么？我期望答案应该是Na=1.0为什么你期望它？你没有任何if语句捕捉sesimic_source=10，而且你返回的是Na==1.0，它将返回一个布尔值。你期望函数返回一个整数吗？酷，非常感谢。这很有帮助。