Python 如何出口刮痧'；将结果转换为特定的JSON格式？

我使用Scrapy爬行和废弃StackOverflow.com。 这是so.py

import scrapy

class StackOverflowSpider(scrapy.Spider):
    name = 'stackoverflow'
    start_urls = ['http://stackoverflow.com']

    def parse(self, response):
        for href in response.css('.question-summary h3 a::attr(href)'):
            full_url = response.urljoin(href.extract())
            yield scrapy.Request(full_url, callback=self.parse_question)

    def parse_question(self, response):
        yield {
            'link': response.url,
        }

预期结果：so.json（有效的json格式）

然后运行：

scrapy runspider so.py -o so.json

---

结果与预期不符。我被困在这里。

尝试使用

FEED\u FORMAT=jsonlines

设置

scrapy runspider so.py -o so.json --set FEED_FORMAT=jsonlines

如果你想得到

[
   "https://stackoverflow.com/questions/36421917/exponential-number-in-custom-number-format-of-excel",
   "https://stackoverflow.com/questions/36421343/can-not-install-requirements-txt",
   "https://stackoverflow.com/questions/36418815/difference-between-two-approaches-to-pass-parameters-to-web-server",
   "https://stackoverflow.com/questions/36421743/sharing-an-oracle-database-connection-between-simultaneous-celery-tasks",
   "https://stackoverflow.com/questions/36421941/jquery-add-css-style",
]

---

您应该编写自己的ItemExporter，

这是运行上述命令后的结果：它仍然不符合我的预期结果。在应用修改后的答案后，我运行命令，然后得到结果：。这不是预期的结果。帮我解决这个问题！

[
   "https://stackoverflow.com/questions/36421917/exponential-number-in-custom-number-format-of-excel",
   "https://stackoverflow.com/questions/36421343/can-not-install-requirements-txt",
   "https://stackoverflow.com/questions/36418815/difference-between-two-approaches-to-pass-parameters-to-web-server",
   "https://stackoverflow.com/questions/36421743/sharing-an-oracle-database-connection-between-simultaneous-celery-tasks",
   "https://stackoverflow.com/questions/36421941/jquery-add-css-style",
]