将2个值放入一个dict python

嘿，我想把两个值放到一个dict中，但不确定如何实现这一点。我希望它看起来像这样

{'Feb  7': {'89.249.209.92': 15},
 'Feb  8': {'66.30.90.148': 14, '72.153.93.203': 14, '92.152.92.123': 5},
 'Jan 10': {'213.251.192.26': 13, '218.241.173.35': 15}}

这里是我目前的代码和我目前在dict中得到的内容

desc_ip = {}

count_ip = 0

    for line in myfile:
        if 'Failed password for' in line:

            line_of_list = line.split()

            ip_address = ' '.join(line_of_list[0:2])
            ip_address = line_of_list[-4]
            if ip_address in desc_ip:
                count_ip = desc_ip[ip_address]
                count_ip = count_ip +1
                desc_ip[ip_address] = count_ip
                #zero out the temporary counter as a precaution
                count_ip =0
            else:
                desc_ip[ip_address] = 1

    for ip in desc_ip.keys():
        print ip ,' has', desc_ip[ip] , ' attacks'

这是我目前的口述

{'213.251.192.26': 13,
 '218.241.173.35': 15,
 '66.30.90.148': 14,
 '72.153.93.203': 14,
 '89.249.209.92': 15,
 '92.152.92.123': 5}

这里是文件中的几行

Jan 10 09:32:09 j4-be03 sshd[3876]: Failed password for root from 218.241.173.35 port 47084 ssh2
Feb  7 17:19:24 j4-be03 sshd[10740]: Failed password for root from 89.249.209.92 port 46752 ssh2

---

您需要一个dict of dict，因此使用日期作为键，并为每个日期创建一个dict。

您需要一个dict of dict，因此使用日期作为键，并为每个日期创建一个dict。

非常可扩展的答案使用Autovification类：

date = 'Feb  7'
ip = '89.249.209.92'
count = 15

d = {}
d[date] = {ip: count}

使用一些示例数据：

sample_text = '''Feb 7 :  89.249.209.92
Feb 7 :  89.249.209.92
Feb 7 :  89.249.209.92
Feb 8 :  89.249.209.92
Jan 10 :  218.241.173.35'''

快速读取数据可得出：

A = AutoVivification()

for line in sample_text.split('\n'):
    date, IP = map(str.strip,line.split(':'))
    if IP not in A[date]: A[date][IP] = 0
    A[date][IP] += 1


>>>> {'Jan 10': {'218.241.173.35': 1}, 'Feb 8': {'89.249.209.92': 1}, 'Feb 7': {'89.249.209.92': 3}}

---

请注意，AutoVivification类不知道嵌套的深度。因此，您需要通过显式设置键的值来设置深度，如

a[date][IP]=0

非常可扩展的答案使用Autovification类：

使用一些示例数据：

sample_text = '''Feb 7 :  89.249.209.92
Feb 7 :  89.249.209.92
Feb 7 :  89.249.209.92
Feb 8 :  89.249.209.92
Jan 10 :  218.241.173.35'''

快速读取数据可得出：

A = AutoVivification()

for line in sample_text.split('\n'):
    date, IP = map(str.strip,line.split(':'))
    if IP not in A[date]: A[date][IP] = 0
    A[date][IP] += 1


>>>> {'Jan 10': {'218.241.173.35': 1}, 'Feb 8': {'89.249.209.92': 1}, 'Feb 7': {'89.249.209.92': 3}}

---

请注意，AutoVivification类不知道嵌套的深度。因此，您需要通过显式设置键的值来设置深度，如

a[date][IP]=0

我假设每行中都有日期：

>>> sample_text = '''Feb 7 :  Failed password for 89.249.209.92
Feb 7 :  Failed password for 89.249.209.92
Feb 7 :  Failed password for 89.249.209.92
Feb 8 :  Failed password for 89.249.209.92
Jan 10 :  Failed password for 218.241.173.35'''
>>> desc_ip = {}
>>> for line in sample_text.split('\n'):
    if 'Failed password for' in line:
        line_of_list = line.split()
        ip_address = line_of_list[6]
        date = ' '.join(line_of_list[0:2])
        if not date in desc_ip:
            desc_ip[date] = {}
        if not ip_address in desc_ip[date]:
            desc_ip[date][ip_address] = 0
        desc_ip[date][ip_address] += 1


>>> desc_ip
{'Jan 10': {'218.241.173.35': 1}, 'Feb 8': {'89.249.209.92': 1}, 'Feb 7': {'89.249.209.92': 3}}
>>> 

---

我可以使用

defaultdict

来避免测试，例如

如果不是desc\u ip中的date

，但是这里我们需要

defaultdict

的

defaultdict

（比如

desc\u ip=defaultdict（lambda:defaultdict（int））

）和IMHO，这会降低可读性。

我假设每一行都有日期：

>>> sample_text = '''Feb 7 :  Failed password for 89.249.209.92
Feb 7 :  Failed password for 89.249.209.92
Feb 7 :  Failed password for 89.249.209.92
Feb 8 :  Failed password for 89.249.209.92
Jan 10 :  Failed password for 218.241.173.35'''
>>> desc_ip = {}
>>> for line in sample_text.split('\n'):
    if 'Failed password for' in line:
        line_of_list = line.split()
        ip_address = line_of_list[6]
        date = ' '.join(line_of_list[0:2])
        if not date in desc_ip:
            desc_ip[date] = {}
        if not ip_address in desc_ip[date]:
            desc_ip[date][ip_address] = 0
        desc_ip[date][ip_address] += 1


>>> desc_ip
{'Jan 10': {'218.241.173.35': 1}, 'Feb 8': {'89.249.209.92': 1}, 'Feb 7': {'89.249.209.92': 3}}
>>> 

---

我可以使用

defaultdict

来避免测试，例如

if not date in desc_ip

，但是这里我们需要

defaultdict

的

defaultdict

（比如

desc_ip=defaultdict（lambda:defaultdict（int））

）和IMHO，这会降低可读性。

您能发布几行示例输入吗（

myfile

），为了更方便地使用您的代码段？请查看以下内容：[Python嵌套字典][1][1]：能否发布几行示例输入（

myfile

），以便更方便地使用您的代码段？请查看以下内容：[Python嵌套字典][1][1]：