Python 使用递归查找嵌套dict的值并返回dict的键

Python 使用递归查找嵌套dict的值并返回dict的键,python,python-3.x,dictionary,Python,Python 3.x,Dictionary,我有一个练习,其中生日字典如下: birthdays = {"Anne": {"month":"Jan","day":"27"}, "Mike":{"month":"Feb","day":"13"}, "Nicolas":{"month":"Jun","day":14}, "Marta": {"month":"Jan","day":16}} 问题是定义一个函数,给定一个月,该函数将打印出该月所有生日的人的列表,以及日期 以下是到目前为止我得到的信息:

我有一个练习,其中生日字典如下:

    birthdays = 
    {"Anne": {"month":"Jan","day":"27"},
    "Mike":{"month":"Feb","day":"13"},
    "Nicolas":{"month":"Jun","day":14}, 
    "Marta": {"month":"Jan","day":16}}
问题是定义一个函数,给定一个月,该函数将打印出该月所有生日的人的列表,以及日期

以下是到目前为止我得到的信息:

    def birthbymonth(book, month):
        for k,v in book.items():
            if isinstance(v, dict):
                birthbymonth(v,month)           
            else:
                if month == v:
                    print(book)
当称为birthbymonth(生日,“Jan”)时,打印:


但是我不知道如何打印那些有生日的人的名字。

我看不出有任何理由在这里使用递归

def birthbymonth(book, month):
    for person,birthday in book.items():
        if birthday['month'] == month:
            print('{}: {} {}'.format(person, birthday['month'], birthday['day']))

正如其他人指出的,不需要递归。相反,请使用列表:

birthdays = {"Anne": {"month":"Jan","day":"27"},
"Mike":{"month":"Feb","day":"13"},
"Nicolas":{"month":"Jun","day":14}, 
"Marta": {"month":"Jan","day":16}}
def dates(birthdays, month):
   return ["{}: {}".format(a, b['day']) for a, b in birthdays.items() if b['month'] == month]

print(dates(birthdays, 'Jan'))
输出:

['Marta: 16', 'Anne: 27']

如果您真的想使用递归(不推荐用于此问题),可以对现有代码进行一些修改:

birthdays = {
    "Anne": {"month":"Jan","day":27},
    "Mike": {"month":"Feb","day":13},
    "Nicolas": {"month":"Jun","day":14},
    "Marta": {"month":"Jan","day":16}
}

def birthbymonth(book, month):
    names = []
    for k,v in book.items():
        if isinstance(v, dict):
            names += [(k, book[k]["day"])] if birthbymonth(v,month) is True else []
        else:
            if month == v:
                return True
    return names

print(birthbymonth(birthdays, 'Jan'))
#[('Marta', 16), ('Anne', 27)]
这里有一个解决方案:

birthdays = {"Anne": {"month":"Jan","day":"27"},
             "Mike": {"month":"Feb","day":"13"},
             "Nicolas": {"month":"Jun","day":14}, 
             "Marta": {"month":"Jan","day":16}}

{k: v['day'] for k, v in birthdays.items() if v['month']=='Jan'}

# {'Anne': '27', 'Marta': 16}
birthdays = {"Anne": {"month":"Jan","day":"27"},
             "Mike": {"month":"Feb","day":"13"},
             "Nicolas": {"month":"Jun","day":14}, 
             "Marta": {"month":"Jan","day":16}}

{k: v['day'] for k, v in birthdays.items() if v['month']=='Jan'}

# {'Anne': '27', 'Marta': 16}