Python：十进制转换为时间格式

我想将十进制时间列表（HH，HHH）转换为时间格式HH:MM:SS

16.       ,   16.00000381,  16.00000572,  16.00000954,
16.00001144,  16.00001335,  16.00001717,  16.00001907,
16.00002098,  16.0000248 ,  16.00002861,  16.00003052,
16.00003433,  16.00003624,  16.00003815,  16.00004196,
16.00004387,  16.00004768,  16.00004959,  16.00005341

有没有办法用python实现这一点

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谢谢

假设这些值代表小时：

In [86]: import datetime as DT
In [87]: data = [16.       ,   16.00000381,  16.00000572,  16.00000954,
16.00001144,  16.00001335,  16.00001717,  16.00001907,
16.00002098,  16.0000248 ,  16.00002861,  16.00003052,
16.00003433,  16.00003624,  16.00003815,  16.00004196,
16.00004387,  16.00004768,  16.00004959,  16.00005341]
   ....:    ....:    ....:    ....: 
In [88]: map(str, [DT.timedelta(seconds=x*60*60.0) for x in data])
Out[88]: 
['16:00:00',
 '16:00:00.013716',
 '16:00:00.020592',
 '16:00:00.034344',...
 '16:00:00.157932',
 '16:00:00.171648',
 '16:00:00.178524',
 '16:00:00.192276']

---

假设这些值代表小时数：

In [86]: import datetime as DT
In [87]: data = [16.       ,   16.00000381,  16.00000572,  16.00000954,
16.00001144,  16.00001335,  16.00001717,  16.00001907,
16.00002098,  16.0000248 ,  16.00002861,  16.00003052,
16.00003433,  16.00003624,  16.00003815,  16.00004196,
16.00004387,  16.00004768,  16.00004959,  16.00005341]
   ....:    ....:    ....:    ....: 
In [88]: map(str, [DT.timedelta(seconds=x*60*60.0) for x in data])
Out[88]: 
['16:00:00',
 '16:00:00.013716',
 '16:00:00.020592',
 '16:00:00.034344',...
 '16:00:00.157932',
 '16:00:00.171648',
 '16:00:00.178524',
 '16:00:00.192276']

一次：

import datetime
x = 21.234768653
hour = int(x)
minute = int((x - int(x))*60.0)
second = int(((x - int(x))*60 - int((x - int(x))*60.0))*60.0)
(datetime.time(hour, minute, second)).strftime('%H:%M:%S')

要查看时间列表，请执行以下操作：

times = [(datetime.time(int(x), int((x - int(x))*60.0), int(((x - int(x)) * 60 - int((x - int(x))*60.0))*60.0))).strftime('%H:%M:%S') for x in time_list]

一次：

import datetime
x = 21.234768653
hour = int(x)
minute = int((x - int(x))*60.0)
second = int(((x - int(x))*60 - int((x - int(x))*60.0))*60.0)
(datetime.time(hour, minute, second)).strftime('%H:%M:%S')

要查看时间列表，请执行以下操作：

times = [(datetime.time(int(x), int((x - int(x))*60.0), int(((x - int(x)) * 60 - int((x - int(x))*60.0))*60.0))).strftime('%H:%M:%S') for x in time_list]

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在上面的数据16.0001144中，16代表什么和.00001144代表什么？16.00000381是带小数的小时，我可以将每个元素转换为秒乘以3600，但这样做很复杂，以时间格式HH:MM:SS:ms（ms=毫秒）进行排列例如，16.00001144是一个16:00:00:41.18，在上面的数据16.0001144中，16代表什么和.00001144代表什么？16.00000381是小时及其小数，我可以将每个元素转换为秒乘以3600，但这样做很复杂，以时间格式HH:MM:SS:ms（ms=毫秒）排列例如，16.00001144是一个16:00:00:41.18抱歉，我有点不清楚，这是正确的UNUTBU，值是小时，我想将它们转换为HH:MM:SS:ms（ms=毫秒）@nandhos:

timedelta（）

具有

.microseconds

属性。相关：抱歉，我有点不清楚，这是正确的UNUTBU，值是小时，我想将它们转换为HH:MM:SS:ms（ms=毫秒）@nandhos:

timedelta（）

具有

。微秒
属性。相关的：