使用套接字编程Python发送图像

我正在尝试使用python中的套接字编程发送一个图像文件。我可以发送一个文本文件。但我一直在尝试发送一个图像文件，打开它并读取图像文件的字符串内容，然后发送字符串并在客户端接收，然后将其写入另一个目录中同名的文件，但我无法打开该文件。另外，我在下面发布我的代码，注释的部分表明我已经尝试过了。此外，我在发送整数

size

时遇到问题，但我在另一侧接收到一些随机字符串

这是服务器脚本

import socket
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.bind(("", 5000))
server_socket.listen(5)
import os


client_socket, address = server_socket.accept()
print "Conencted to - ",address,"\n"
while (1):
    choice = client_socket.recv(1024)
    choice = int(choice)
    if(choice == 1):
        data = client_socket.recv(1024)
        print "The following data was received - ",data
        print "Opening file - ",data
        fp = open(data,'r')
        strng = fp.read()
        size = os.path.getsize(data)
        size = str(size)
        client_socket.send(size)
        client_socket.send (strng)
        #client_socket.close()

    if (choice == 2):
        data = client_socket.recv(1024)
        print "The following data was received - ",data
        print "Opening file - ",data
        fp = open(data,'r')
        strng = fp.read()
        #strng = str(fp)
        size = os.path.getsize(data)
        print size
        size = str(size)
        print size
        client_socket.send(size)
        client_socket.send (strng)
        #client_socket.close()

这是客户端脚本-

#!/usr/bin/python
# TCP client example
import socket,os
client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client_socket.connect(("", 5000))
k = ' '
size = 1024

while(1):
    print "Do you want to transfer a \n1.Text File\n2.Image\n3.Video\n"
    k = raw_input()
    client_socket.send(k)
    k = int (k)
    if(k == 1):
        print "Enter file name\n"
        strng = raw_input()
        client_socket.send(strng)
        size = client_socket.recv(1024)
        size = int(size)
        print "The file size is - ",size," bytes"
        size = size*2
        strng = client_socket.recv(size)
        print "\nThe contents of that file - "
        print strng

    if (k==2):
        print "Enter file name of the image with extentsion (example: filename.jpg,filename.png) - "
        fname = raw_input()
        client_socket.send(fname)
        size = client_socket.recv(1)
        print size
        #size = int(size)
        print "The file size is - ",size
        size = size*2
        strng = client_socket.recv(256456)
        print "\nThe file will be saved and opened- "
        fname = 'downloads/'+fname
        nf = open(fname,'w')
        nf.write(strng)
        nf.close()
        fname = 'viewnior '+ fname
        print fname
        os.system(fname)

我在Crunchbang Linux上编程——这是一个非官方的基于Debian的发行版

---

viewnior是图像查看器。

我在我的系统（Ubuntu 11.10）上运行了相同的代码，我发现以字符串形式发送大小存在问题。当我插入逻辑来处理那个部分时，它运行得很顺利。我也可以打开文件。 这就是我如何解决您的问题的方法： 客户代码（client.py）的第一次更改是在接受大小并发送确认时：-

size = ' '
while(1):
   tmpsize = client_socket.recv(1)
   if tmpsize.isdigit() == True:
      print "Here : ",tmpsize
      size += tmpsize
   else:
      break

client_socket.send("received")

第二个更改是在服务器端（server.py）代码中，以接受确认：-

client_socket.send(size)
ack = client_socket.recv(1024)
if ack == "received":
   client_socket.send (strng)

---

我希望这能帮助你解决你的问题。

谢谢你，桑凯特：D我在发送大块数据时遇到问题，所以我将其拆分为512字节，现在它甚至可以完美地用于视频：D只需要添加pygtk接口，以确认接收和发送文件：D

#!/usr/bin/python
# TCP client example
import socket,os
client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client_socket.connect(("", 5005))
k = ' '
size = 1024

while(1):
    print "Do you want to transfer a \n1.Text File\n2.Image\n3.Video\n"
    k = raw_input()
    client_socket.send(k)
    k = int (k)
    if(k == 1):
        print "Enter file name\n"
        strng = raw_input()
        client_socket.send(strng)
        size = client_socket.recv(1024)
        size = int(size)
        print "The file size is - ",size," bytes"
        size = size*2
        strng = client_socket.recv(size)
        print "\nThe contents of that file - "
        print strng

    if (k==2 or k==3):
        print "Enter file name of the image with extentsion (example: filename.jpg,filename.png or if a video file then filename.mpg etc) - "
        fname = raw_input()
        client_socket.send(fname)
        fname = 'documents/'+fname
        fp = open(fname,'w')
        while True:
            strng = client_socket.recv(512)
            if not strng:
                break
            fp.write(strng)
        fp.close()
        print "Data Received successfully"
        exit()
        #data = 'viewnior '+fname
        #os.system(data)

这是服务器代码

import socket
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.bind(("", 5005))
server_socket.listen(5)
import os


client_socket, address = server_socket.accept()
print "Conencted to - ",address,"\n"
while (1):
    choice = client_socket.recv(1024)
    choice = int(choice)
    if(choice == 1):
        data = client_socket.recv(1024)
        print "The following data was received - ",data
        print "Opening file - ",data
        fp = open(data,'r')
        strng = fp.read()
        size = os.path.getsize(data)
        size = str(size)
        client_socket.send(size)
        client_socket.send (strng)
        #client_socket.close()

    if (choice == 2 or choice == 3):
        data = client_socket.recv(1024)
        print "The following data was received - ",data
        print "Opening file - ",data
        img = open(data,'r')
        while True:
            strng = img.readline(512)
            if not strng:
                break
            client_socket.send(strng)
        img.close()
        print "Data sent successfully"
        exit()
        #data = 'viewnior '+data
        #os.system(data)

---

你试过调试它吗<代码>打印报告（客户端）？会尝试的，谢谢。我在新创建的文件和原始文件之间尝试了vimdiff，结果发现文件是相同的，新创建的图像仍然无法打开。原始图像和克隆图像的大小相同，内容也相同。谢谢sanket。我解决了这个问题。但事实证明我在发送大文件时遇到了问题，所以我决定一行一行地发送它们。这是修改后的代码：D首先感谢您的帮助。但是我有个问题。当运行发送图像的两个脚本时，它会打印成功发送的

数据

并停止，尽管接收到的图像应该在代码中使用后者。我是这样使用它的

input\u image=image.open（“data”）.convert（“L”）.resize（（100100））

我无法在windows上运行它。将两个文件中的

open（data，'r'）

更改为

open（data，'rb'）

，并将

readline

替换为

read

以二进制方式传输数据，解决了我的问题