运行flyway命令只需打印帮助并在python脚本中退出即可
所以我有一个Python脚本,我正在通过AWS代码构建运行它。它使用flyway命令行docker容器执行以下命令:运行flyway命令只需打印帮助并在python脚本中退出即可,python,flyway,aws-codebuild,Python,Flyway,Aws Codebuild,所以我有一个Python脚本,我正在通过AWS代码构建运行它。它使用flyway命令行docker容器执行以下命令: cmd = 'flyway -user=' + connection_items['username'] + ' -password=' + connection_items['password'] + ' migrate' os.system(cmd) # I know this is insecure... just trying to get a migration to
cmd = 'flyway -user=' + connection_items['username'] + ' -password=' + connection_items['password'] + ' migrate'
os.system(cmd) # I know this is insecure... just trying to get a migration to run
它执行flyway时没有任何参数,只是打印帮助并退出。有人对我做错了什么有什么建议吗?我还不能通过子流程
模块运行(我有路径问题)
谢谢 它看起来更像是一个shell扩展问题,而不是代码构建问题 你的buildspec很混乱,我重写了你的buildspec如下。我希望这有助于:
---
version: 0.2
phases:
install:
runtime-versions:
python: 3.7
commands:
- echo "Installing flyway..."
- nohup /usr/local/bin/dockerd --host=unix:///var/run/docker.sock --host=tcp://0.0.0.0:2375 --storage-driver=overlay&
- timeout 15 sh -c "until docker info; do echo .; sleep 1; done"
- echo "docker run --rm flyway/flyway:6.0.4 -url=jdbc:mysql://db -schemas=myschema -user=root -password=P@ssw0rd -connectRetries=60 migrate" > /usr/local/bin/flyway
- chmod +x /usr/local/bin/flyway
-
build:
commands:
- echo building...
- /usr/local/bin/flyway
- python MigrateDatabase.py
另外,我确信您已经将项目环境的特权模式设置为true。能否共享buildspec.yml将整个flyway命令(包括参数)放入/usr/local/bin中的脚本中是个好主意