python中的lappy等价函数
我有7个电话号码条目的数据帧df,我想创建新的重命名列,比如ph1。。ph7,并用清理过的电话号码值填充,即删除空格“/”、“-”、“+”等 有了R,我可以很容易地使用Lappy。在Python中有什么方法可以做到这一点吗? 我知道do.call()也可以做同样的事情,但面临着同样的问题python中的lappy等价函数,python,python-3.x,pandas,Python,Python 3.x,Pandas,我有7个电话号码条目的数据帧df,我想创建新的重命名列,比如ph1。。ph7,并用清理过的电话号码值填充,即删除空格“/”、“-”、“+”等 有了R,我可以很容易地使用Lappy。在Python中有什么方法可以做到这一点吗? 我知道do.call()也可以做同样的事情,但面临着同样的问题 con_1 <- con[, c("ph1", "ph2", "ph3", "ph4", "ph5", "ph6", "ph7") := lapply(.SD, funct
con_1 <- con[, c("ph1", "ph2", "ph3", "ph4", "ph5", "ph6", "ph7") :=
lapply(.SD, function(x) { gsub(paste(unlist(list(" ", "/", "-", "+")), collapse = "|"), replace = "", x) }),
.SDcols = c("phone1", "phone2", "phone3", "phone4", "phone5", "phone6", "phone7")]
con_1假设您拥有以下数据帧(与您的数据帧完全不同,因为您的数据帧中不会更新任何内容):
您可以定义应用于每个单元格的函数<代码>应用映射
执行此操作。这里我定义了一个函数clean\u df
,它将删除+
、-
和/
:
def clean_up_df(data):
rep = data.replace('/', '') # Replace '/' by ''
rep = rep.replace('-', '') # Replace '-' by ''
rep = rep.replace('+', '') # Replace '+' by ''
return rep
# Columns to process
phone_columns = ['phone1', 'phone2', 'phone3',
'phone4', 'phone5', 'phone6', 'phone7']
# Processing the function clean_up_df
df[phone_columns] = df[phone_columns].applymap(clean_up_df)
# Display
print(df)
# kac play_id phone1 phone2 phone3 phone4 phone5 phone6 phone7
# 0 5004490 20002075 0900031349 090891349
# 1 5003807 00601731 088235311
# 2 5003808 00601731 088235311
现在,如果要处理特定列,可以使用apply
和axis=1
这意味着:将此函数应用于数据帧的每一行。
这里有一个例子:
# column to proceed
phone_col_name = "phone1"
# Same function with the column specified
def clean_up(data):
rep = data[phone_col_name].replace('/', '')
rep = rep.replace('-', '')
rep = rep.replace('+', '')
return rep
# Process
df[phone_col_name] = df.apply(clean_up, axis=1)
# Display
print(df)
# kac play_id phone1 phone2 phone3 phone4 phone5 phone6 phone7
# 0 5004490 20002075 0900031349 090891349
# 1 5003807 00601731 08+82+35+31/1
# 2 5003808 00601731 08/82/35/31/1
您的R代码中的
con
是什么?您认为数据帧在unput中是什么样子的?您可以使用apply
在所有DataFrame上计算函数。con是R DataFrame,但我想将其转换为等效的python代码。我们可以用与R相同的方式使用数据帧类型:熊猫还是火花?您可以标记这两个库。顺便说一下,这是R数据。表
代码不是标准的R库。
def clean_up_df(data):
rep = data.replace('/', '') # Replace '/' by ''
rep = rep.replace('-', '') # Replace '-' by ''
rep = rep.replace('+', '') # Replace '+' by ''
return rep
# Columns to process
phone_columns = ['phone1', 'phone2', 'phone3',
'phone4', 'phone5', 'phone6', 'phone7']
# Processing the function clean_up_df
df[phone_columns] = df[phone_columns].applymap(clean_up_df)
# Display
print(df)
# kac play_id phone1 phone2 phone3 phone4 phone5 phone6 phone7
# 0 5004490 20002075 0900031349 090891349
# 1 5003807 00601731 088235311
# 2 5003808 00601731 088235311
# column to proceed
phone_col_name = "phone1"
# Same function with the column specified
def clean_up(data):
rep = data[phone_col_name].replace('/', '')
rep = rep.replace('-', '')
rep = rep.replace('+', '')
return rep
# Process
df[phone_col_name] = df.apply(clean_up, axis=1)
# Display
print(df)
# kac play_id phone1 phone2 phone3 phone4 phone5 phone6 phone7
# 0 5004490 20002075 0900031349 090891349
# 1 5003807 00601731 08+82+35+31/1
# 2 5003808 00601731 08/82/35/31/1