使用X和Y在matplotlib上使用python绘制轴承 我在地图上有3个已知位置，使用X，Y matplotlib使用子地块，我需要绘制其中一个塔的方位，并在地图上放置一条线 我目前使用X，Y作为起始位置，箭头/直线作为结束位置。但我想知道如何用轴承代替线的末端，而不是x，y。我目前正在研究向量，但运气不好

我的代码在下面，任何帮助都会很好

import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
import math


df = pd.read_csv("Book1.csv")
df.head()
tower1x = [51.69557]
tower1y = [-3.34197]
tower2x = [51.69673]
tower2y = [-3.34235]

tower3x = [51.69630]
tower3y = [-3.34090]


BBox = (df.longitude.min(), df.longitude.max(),
        df.latitude.min(), df.latitude.max())
print (BBox)
     
ruh_m = plt.imread('map.png')

fig, ax = plt.subplots(figsize = (12,12))



ax.scatter(tower1x, tower1y, zorder=1, alpha= 0.5, c='red', s=50, label="Tower 1")
ax.scatter(tower2x, tower2y, zorder=1, alpha= 0.5, c='blue', s=50, label="Tower 2")
ax.scatter(tower3x, tower3y, zorder=1, alpha= 0.5, c='green', s=50, label="Tower 3")

ax.annotate("",xy=(51.69557,-3.34197), xytext=**(51.69799, -3.34155)**, textcoords='data',
            arrowprops=dict(arrowstyle="<-", connectionstyle="arc3"),) # point from tower 1 using X,Y

ax.set_title('Plotting Towers in Aberfan')
ax.set_xlim(BBox[0],BBox[1])
ax.set_ylim(BBox[2],BBox[3])
ax.imshow(ruh_m, zorder=0, extent = BBox, aspect= 'equal')


plt.legend()
plt.show()

将numpy导入为np
作为pd进口熊猫
将matplotlib.pyplot作为plt导入
输入数学
df=pd.read\u csv（“Book1.csv”）
df.head（）
tower1x=[51.69557]
tower1y=[-3.34197]
tower2x=[51.69673]
tower2y=[-3.34235]
tower3x=[51.69630]
tower3y=[-3.34090]
BBox=（df.longitude.min（），df.longitude.max（），
df.latitude.min（），df.latitude.max（））
打印（BBox）
ruh_m=plt.imread（'map.png'）
图，ax=plt.子批次（图尺寸=（12,12））
最大散射（塔楼1x，塔楼1y，索德=1，阿尔法=0.5，c='红色'，s=50，标签=“塔楼1”）
最大散射（tower2x，tower2y，zorder=1，alpha=0.5，c='blue'，s=50，label=“2号塔”）
最大散射（tower3x，tower3y，zorder=1，alpha=0.5，c='绿色'，s=50，label=“塔3”）
ax.注释（“，xy=（51.69557，-3.34197），xytext=**（51.69799，-3.34155）**，textcoords='data'，
arrowprops=dict（arrowstyle=“这只是三角函数，不是吗？@jtlz2是的，如果我考虑了距离，我就不会有这些数据，如果我考虑了，会容易得多：（我只需要方位，如果我在所有三座塔楼上取方位，我就能得到我的位置，这就是我的最终目标。还有：，@jtlz2完美伙伴谢谢，我会试试的，看来这就是我要找的for@jtlz2这是上面的代码，它正在工作：）比ks的链接pal
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
import math


df = pd.read_csv("Grids.csv")
df.head()
##
###X and Y Coordinates using www.openstreetmap.org
BBox = (df.longitude.min(), df.longitude.max(),
        df.latitude.min(), df.latitude.max())


#Signal power
s1 = int(input("Enter power from tower 1: "))
s2 = int(input("Enter power from tower 2: "))
s3 = int(input("Enter power from tower 3: "))

#weight of signal
w1 = [s1 / ( s1 + s2 +  s3 )]
w2 = [s2 / ( s1 + s2  + s3 )] 
w3 = [s3 / ( s1 + s2 + s3 )]

#Tower locations 
tower1_lat = np.array ([51.6985630])
tower1_lon = np.array ([-3.3410239])
##
tower2_lat = np.array ([51.6984699])
tower2_lon = np.array ([-3.3400422])
##
tower3_lat = np.array([51.6980743])
tower3_lon = np.array([-3.3406511])

#Your location using the above values
Locaion_Longitude = [tower1_lat * w1 + tower2_lat * w2 + tower3_lat * w3 ]
Locaion_Latitude = [tower1_lon * w1 + tower2_lon * w2 + tower3_lon* w3 ]
print (Locaion_Longitude)
print (Locaion_Latitude)



    
map_fig = plt.imread('map.png')



fig, ax = plt.subplots(dpi=150,figsize = (12,7))



ax.scatter(tower1_lon, tower1_lat, zorder=1, alpha= 0.5, c='red', s=50, label="Tower 1")
ax.scatter(tower2_lon, tower2_lat, zorder=1, alpha= 0.5, c='blue', s=50, label="Tower 2")
ax.scatter(tower3_lon, tower3_lat, zorder=1, alpha= 0.5, c='green', s=50, label="Tower 3")
ax.scatter(Locaion_Longitude, Locaion_Latitude, zorder=1, c='yellow', s=50, label="Your location")


ax.tick_params (axis='y', which='major', labelsize=5)
ax.tick_params (axis='x', which='major', labelsize=5)#axis settings
ax.set_title('Plotting Towers in Aberfan')
ax.set_xlim(BBox[0],BBox[1])
ax.set_ylim(BBox[2],BBox[3])
ax.imshow(map_fig, zorder=0, extent = BBox, aspect= "auto")


mng = plt.get_current_fig_manager() #full screen
mng.window.state("zoomed")

plt.legend()

plt.show()

enter code here