Python 如何重新排列Numpy阵列:二维到三维?
我有以下数组Python 如何重新排列Numpy阵列:二维到三维?,python,arrays,numpy,Python,Arrays,Numpy,我有以下数组 >>> import numpy as np >>> a = np.arange(100).reshape(20,5) >>> a array([[ 0, 1, 2, 3, 4], [ 5, 6, 7, 8, 9], [10, 11, 12, 13, 14], [15, 16, 17, 18, 19], [20, 21, 22, 23, 24],
>>> import numpy as np
>>> a = np.arange(100).reshape(20,5)
>>> a
array([[ 0, 1, 2, 3, 4],
[ 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24],
[25, 26, 27, 28, 29],
[30, 31, 32, 33, 34],
[35, 36, 37, 38, 39],
[40, 41, 42, 43, 44],
[45, 46, 47, 48, 49],
[50, 51, 52, 53, 54],
[55, 56, 57, 58, 59],
[60, 61, 62, 63, 64],
[65, 66, 67, 68, 69],
[70, 71, 72, 73, 74],
[75, 76, 77, 78, 79],
[80, 81, 82, 83, 84],
[85, 86, 87, 88, 89],
[90, 91, 92, 93, 94],
[95, 96, 97, 98, 99]])
如何将其重塑为:
>>> a
array([[[ 0, 1, 2, 3, 4],
[ 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24]],
[[25, 26, 27, 28, 29],
[30, 31, 32, 33, 34],
[35, 36, 37, 38, 39],
[40, 41, 42, 43, 44],
[45, 46, 47, 48, 49]],
[[50, 51, 52, 53, 54],
[55, 56, 57, 58, 59],
[60, 61, 62, 63, 64],
[65, 66, 67, 68, 69],
[70, 71, 72, 73, 74]],
[[75, 76, 77, 78, 79],
[80, 81, 82, 83, 84],
[85, 86, 87, 88, 89],
[90, 91, 92, 93, 94],
[95, 96, 97, 98, 99]]])
您只需重新塑形,如评论中提到的@hpaulj所示:
a = a.reshape(4,5,5)
您只需重新塑形,如评论中提到的@hpaulj所示:
a = a.reshape(4,5,5)
a.重塑(4,5,5)
做你想做的事吗?在你提供的重新排列的示例中,次矩阵分别包含5、6、5、4行。你确定这就是你想要的吗?这不再是矩阵了。@hpaulj我的错。是的,你说得对。我已经更正了我的打字错误。是否重新塑造(4,5,5)做你想做的事?你提供的重新排列的示例中的次矩阵分别包含5、6、5、4行。你确定这就是你想要的吗?这不再是矩阵了。@hpaulj我的错。是的,你说得对。我已经改正了我的打字错误。