python递增字符循环

好的，我正在努力创建一个增量列表循环

希望实现执行以下操作的循环： 循环遍历字符集1 a-Z。如果未找到匹配项，则添加到循环中，以便aa ZZ等。似乎找不到一个好方法来做循环

import itertools
result = "password"
charset1 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
charset2 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
charcount = 1

while i != result
    finalchar = charset1[-1]
    finalset = charset1[-1] * charcount
    for check in 

---

您可以使用以下使用

itertools.product

和

repeat

参数作为模板的方法：

from string import ascii_letters
from itertools import product

for i in range(1, 3): # do 1 and 2 chars
    chars = product(ascii_letters, repeat=i)
    for combo in chars:
        print(''.join(combo))

---

通过定义

charset1=“abcdefghijklmnopqrstuvwxyz”

等，或者通过

导入字符串，可以节省大量工作；charset1=string.lowercase；charset2=string.letters

。nvm找到了答案。谢谢你的帮助。