Python 如何创建在输入数字时终止的程序？

#程序仅在输入0到9个数字时终止，但如果输入了任何数字，我希望它终止。

使用

.isdigit（）

。这样试试-

q = []
num = ["1","2","3","4","5","6","7","8","9","0"]
while True:
    dat = float(input("Enter Name: "))
    if dat == "*":
      print(q.pop(0))
    if dat in num :
    break
    else:
      q.append(dat)

---

与其检查

dat

是否为数字，不如检查其任何字符是否为数字：

q = []
#num = ["1","2","3","4","5","6","7","8","9","0"]
while True:
    dat = input("Enter Name: ")
    if dat == "*":
      print(q.pop(0))
    if dat.isdigit() :
        break
    else:
      q.append(dat)

另一种方法是检查函数

isalpha

：

q = []
somedigit = False
while True:
    dat = input("Enter Name: ")
    if dat == "*":
      print(q.pop(0))
    for element in dat:
         if element.isdigit():
             somedigit = True
             break
    if somedigit == True:
        break
    else:
      q.append(dat)

---

@心理学家编辑了这篇文章

q = []
while True:
    dat = input("Enter Name: ")
    if dat == "*":
      print(q.pop(0))
    if not dat.isalpha():
      break
    else:
      q.append(dat)