Python 通过每行应用函数确定句子';结构
我正在尝试添加一个新列,其中包含此数据集每行的句子结构:Python 通过每行应用函数确定句子';结构,python,pandas,spacy,Python,Pandas,Spacy,我正在尝试添加一个新列,其中包含此数据集每行的句子结构: Sentence I ate an apple pie, yesterday. I ate an orange, yesterday. I eat a lemon, today. 为了将此函数应用于每一行,我编写了以下内容: def stru(): nlp = spacy.load('en_core_web_sm',disable=['ner','textcat']) doc = nlp(f
Sentence
I ate an apple pie, yesterday.
I ate an orange, yesterday.
I eat a lemon, today.
为了将此函数应用于每一行,我编写了以下内容:
def stru():
nlp = spacy.load('en_core_web_sm',disable=['ner','textcat'])
doc = nlp(file.Sentence)
pos = ""
for token in doc:
pos += token.pos_ + " "
return
然后df.Struct=df.句子.apply(stru)
我的预期输出如下:
Sentence Struct
I ate an apple pie, yesterday. PRONOUN VERB NOUN ADJECTIVE
I ate an orange, yesterday. PRONOUN VERB NOUN ADJECTIVE
I eat a lemon, today. PRONOUN VERB NOUN ADJECTIVE
您能告诉我它出了什么问题吗?您需要将特定语句传递给函数,并“返回”结果,即pos:
def stru(sentence):
nlp = spacy.load('en_core_web_sm',disable=['ner','textcat'])
doc = nlp(sentence)
pos = ""
for token in doc:
pos += token.pos_ + " "
return pos
我会尝试:doc=nlp(句子)我会尽快标记它,gtomer:)我只是想了解如何获得预期的输出我做了另一次更正。您需要返回结果=位置。请参见上文感谢gtomer。我对句子(论点)有疑问:这不是我的专栏,不是吗?所以,当我将函数应用于我的列时,我应该传递哪个参数?一次传递一行