Python 通过将一个数据帧的列与另一个数据帧的行进行多行操作来获取一个数据帧

我有两个数据帧，形状是m*5和5*n。具有5列的第一个数据帧的列名与具有5行的第二个数据帧的索引相同。我想将第一个数据帧中每行的每个元素与第二个数据帧的前2列相乘，并在第二个数据帧中具有相应的行索引。请查找以下数据框以供参考：

数据帧1：

                       %age_paid_0.0  %age_paid_0.1  %age_paid_0.2  %age_paid_0.3  \
account_angaza_id                                                               
AC005839                0.299221       0.377086       0.454950       0.532814   
AC005842                0.299221       0.299221       0.521691       0.521691   
AC005843                0.299221       0.377086       0.454950       0.532814   
AC005851                0.243604       0.310345       0.354839       0.354839   
AC005852                0.299221       0.377086       0.454950       0.532814   
AC005853                0.299221       0.377086       0.454950       0.532814   
AC005856                0.299221       0.377086       0.454950       0.532814   
AC005858                0.299221       0.377086       0.454950       0.532814   
AC005859                0.332592       0.432703       0.543938       0.650723   
AC005860                0.288098       0.365962       0.421580       0.532814   

                   %age_paid_0.4  %age_paid_0.5  
account_angaza_id                                
AC005839                0.610679       0.688543  
AC005842                0.521691       0.521691  
AC005843                0.610679       0.766407  
AC005851                0.510567       0.555061  
AC005852                0.610679       0.766407  
AC005853                0.610679       0.688543  
AC005856                0.610679       0.766407  
AC005858                0.543938       0.588432  
AC005859                0.650723       0.739711  
AC005860                0.532814       0.632925  

数据帧2：

                      0         1
%age_paid_0.0  0.369886  0.673442
%age_paid_0.1  0.409603  0.374386
%age_paid_0.2  0.425269  0.058336
%age_paid_0.3  0.425229 -0.191075
%age_paid_0.4  0.415484 -0.369895
%age_paid_0.5  0.401384 -0.479141

预期数据帧：

                   0         1
  AC005839     1.xxxxxx  2.xxxxxx
  AC005840     xxxxxxxx  xxxxxxxx
  AC005840     xxxxxxxx  xxxxxxxx

公式是

dataframe3.loc['AC005839',0] = dataframe1.loc['AC005839',%age_paid_0.1]*dataframe2.loc[%age_paid_0.1,0]+dataframe1.loc['AC005839',%age_paid_0.2]*dataframe2.loc[%age_paid_0.2,0]+...+dataframe1.loc['AC005839',%age_paid_0.5]*dataframe2.loc[%age_paid_0.5,0]
dataframe3.loc['AC005839',1] = dataframe1.loc['AC005839',%age_paid_0.1]*dataframe2.loc[%age_paid_0.1,1]+dataframe1.loc['AC005839',%age_paid_0.2]*dataframe2.loc[%age_paid_0.2,1]+...+dataframe1.loc['AC005839',%age_paid_0.5]*dataframe2.loc[%age_paid_0.5,1]

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任何形式的帮助都将不胜感激。基本上，我试图把一个变量转换成与主成分相同的平面。提前谢谢

这是一个点积。由于索引/列标签匹配，您只需：

df1.dot(df2)

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听起来像是点积。谢谢，这很有帮助