提取字典（Python）中以键命名的未指定数量的字典

晚上好,

相信一切都好

目标

我试图将一个字典分解为每个键的单独字典；每个新字典的值都将为空。字典将在稍后阶段使用zip函数填充列表

我的尝试

初始列表（list_towers）将包含不同数量的值和未指定数量的重复值。下面代码中的值对于我的问题是有限的

删除所有重复值后，我会留下一个列表（unique_towers），然后将其压缩到字典（unique_towers_dict）中。所有键都有空白值

我无法找到一个for循环来迭代唯一的目录，为每个键创建一个单独的字典

任何反馈都将不胜感激

我的注释代码如下

from collections import OrderedDict


#The list in reality would have a varying number of values, and an unspecified number of duplicate values
list_towers = ["Tower1", "Tower1", "Tower2", "Tower3", "Tower3", "Tower4", "Tower5", "Tower5"]

print(f"Complete list of Tower values: {list_towers}\n") #prints list of towers; includes duplicates

unique_num_towers = len(set(list_towers)) #extract number of unique values in the set
print(f"Number of Unique Towers: {unique_num_towers}") #prints the unique number of towers

unique_towers = (set(list_towers)) #extracts a unique values from list_towers into the set unique_towers
unique_towers = list(unique_towers) #convert set unique_towers into a list
unique_towers.sort() #sort the list in ascending order
print(f"Names of unique towers in list: {unique_towers}\n")

unique_towers_dict = {} #create an empty dictionary unique_towers_dict
for unique_towers in zip(unique_towers): #assign the lists to the dict
    unique_towers_dict[unique_towers] = [] #assign unique_towers as key; values are empty


print(f"Nested Dictionary: {unique_towers_dict}") #print dictionary; shows empty values; keys are in ascending order

#I can't figure out a for loop to iterate through the unique_towers_dict to create a separate dictionary for each key

---

如果我理解正确，这个循环应该得到正确的答案：

d = {}
for x in unique_towers_dict.keys():
    d[x[0]] = {}

print ("\n", d)

输出

{'Tower1': {}, 'Tower2': {}, 'Tower3': {}, 'Tower4': {}, 'Tower5': {}}