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有python排列问题吗_Python_Python 3.x_Itertools - Fatal编程技术网

有python排列问题吗

有python排列问题吗,python,python-3.x,itertools,Python,Python 3.x,Itertools,我对排列有一些问题!说到python,我真的是个大傻瓜,所以任何帮助都将不胜感激 假设我在文本文件中有一个范围为1-6的列表,例如 看起来像(1,2,3,4,5,6),我想打开said.txt文件,计算这6个数字中N的所有可能组合,直到N=4 当我使用itertools置换时 import itertools x = [1, 2, 3, 4, 5, 6] [p for p in itertools.product(x, repeat=2)] [(1, 1), (1, 2), (1, 3), (1

我对排列有一些问题!说到python,我真的是个大傻瓜,所以任何帮助都将不胜感激

假设我在文本文件中有一个范围为1-6的列表,例如 看起来像(1,2,3,4,5,6),我想打开said.txt文件,计算这6个数字中N的所有可能组合,直到N=4

当我使用itertools置换时

import itertools
x = [1, 2, 3, 4, 5, 6]
[p for p in itertools.product(x, repeat=2)]
[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 
2), (2, 3), 
(2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 
5), (3, 6), 
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 
2), (5, 3), 
 (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6,5), 
(6, 6)]
它输出这样的数字,我真的不想要,因为我一次只能得到一个数字的所有组合-但我想要N个数字的所有可能组合,N的范围从1到4,包括重复,例如:

(1,1), (1,1,1) (1,1,1,1), (1,1,1,1) 
所以我希望它有重复,有不同成员数的组合,但不要超过4个数字组合。我真的很难理解这个概念!如果有任何不合理的地方,请毫不犹豫地问我:)

将产生:

[(1,), (2,), (3,), 
(1, 1), (1, 2), (1, 3), 
(2, 1), (2, 2), (2, 3), 
(3, 1), (3, 2), (3, 3), 
(1, 1, 1), (1, 1, 2), (1, 1, 3), 
(1, 2, 1), (1, 2, 2), (1, 2, 3), 
(1, 3, 1), (1, 3, 2), (1, 3, 3), 
(2, 1, 1), (2, 1, 2), (2, 1, 3), 
(2, 2, 1), (2, 2, 2), (2, 2, 3), 
(2, 3, 1), (2, 3, 2), (2, 3, 3), 
(3, 1, 1), (3, 1, 2), (3, 1, 3), 
(3, 2, 1), (3, 2, 2), (3, 2, 3), 
(3, 3, 1), (3, 3, 2), (3, 3, 3), 
(1, 1, 1, 1), (1, 1, 1, 2), (1, 1, 1, 3), 
(1, 1, 2, 1), (1, 1, 2, 2), (1, 1, 2, 3), 
(1, 1, 3, 1), (1, 1, 3, 2), (1, 1, 3, 3), 
(1, 2, 1, 1), (1, 2, 1, 2), (1, 2, 1, 3), 
(1, 2, 2, 1), (1, 2, 2, 2), (1, 2, 2, 3), 
(1, 2, 3, 1), (1, 2, 3, 2), (1, 2, 3, 3), 
(1, 3, 1, 1), (1, 3, 1, 2), (1, 3, 1, 3), 
(1, 3, 2, 1), (1, 3, 2, 2), (1, 3, 2, 3), 
(1, 3, 3, 1), (1, 3, 3, 2), (1, 3, 3, 3), 
(2, 1, 1, 1), (2, 1, 1, 2), (2, 1, 1, 3), 
(2, 1, 2, 1), (2, 1, 2, 2), (2, 1, 2, 3), 
(2, 1, 3, 1), (2, 1, 3, 2), (2, 1, 3, 3), 
(2, 2, 1, 1), (2, 2, 1, 2), (2, 2, 1, 3), 
(2, 2, 2, 1), (2, 2, 2, 2), (2, 2, 2, 3), 
(2, 2, 3, 1), (2, 2, 3, 2), (2, 2, 3, 3),
(2, 3, 1, 1), (2, 3, 1, 2), (2, 3, 1, 3), 
(2, 3, 2, 1), (2, 3, 2, 2), (2, 3, 2, 3), 
(2, 3, 3, 1), (2, 3, 3, 2), (2, 3, 3, 3), 
(3, 1, 1, 1), (3, 1, 1, 2), (3, 1, 1, 3), 
(3, 1, 2, 1), (3, 1, 2, 2), (3, 1, 2, 3), 
(3, 1, 3, 1), (3, 1, 3, 2), (3, 1, 3, 3), 
(3, 2, 1, 1), (3, 2, 1, 2), (3, 2, 1, 3), 
(3, 2, 2, 1), (3, 2, 2, 2), (3, 2, 2, 3), 
(3, 2, 3, 1), (3, 2, 3, 2), (3, 2, 3, 3), 
(3, 3, 1, 1), (3, 3, 1, 2), (3, 3, 1, 3), 
(3, 3, 2, 1), (3, 3, 2, 2), (3, 3, 2, 3), 
(3, 3, 3, 1), (3, 3, 3, 2), (3, 3, 3, 3)]
将产生:

[(1,), (2,), (3,), 
(1, 1), (1, 2), (1, 3), 
(2, 1), (2, 2), (2, 3), 
(3, 1), (3, 2), (3, 3), 
(1, 1, 1), (1, 1, 2), (1, 1, 3), 
(1, 2, 1), (1, 2, 2), (1, 2, 3), 
(1, 3, 1), (1, 3, 2), (1, 3, 3), 
(2, 1, 1), (2, 1, 2), (2, 1, 3), 
(2, 2, 1), (2, 2, 2), (2, 2, 3), 
(2, 3, 1), (2, 3, 2), (2, 3, 3), 
(3, 1, 1), (3, 1, 2), (3, 1, 3), 
(3, 2, 1), (3, 2, 2), (3, 2, 3), 
(3, 3, 1), (3, 3, 2), (3, 3, 3), 
(1, 1, 1, 1), (1, 1, 1, 2), (1, 1, 1, 3), 
(1, 1, 2, 1), (1, 1, 2, 2), (1, 1, 2, 3), 
(1, 1, 3, 1), (1, 1, 3, 2), (1, 1, 3, 3), 
(1, 2, 1, 1), (1, 2, 1, 2), (1, 2, 1, 3), 
(1, 2, 2, 1), (1, 2, 2, 2), (1, 2, 2, 3), 
(1, 2, 3, 1), (1, 2, 3, 2), (1, 2, 3, 3), 
(1, 3, 1, 1), (1, 3, 1, 2), (1, 3, 1, 3), 
(1, 3, 2, 1), (1, 3, 2, 2), (1, 3, 2, 3), 
(1, 3, 3, 1), (1, 3, 3, 2), (1, 3, 3, 3), 
(2, 1, 1, 1), (2, 1, 1, 2), (2, 1, 1, 3), 
(2, 1, 2, 1), (2, 1, 2, 2), (2, 1, 2, 3), 
(2, 1, 3, 1), (2, 1, 3, 2), (2, 1, 3, 3), 
(2, 2, 1, 1), (2, 2, 1, 2), (2, 2, 1, 3), 
(2, 2, 2, 1), (2, 2, 2, 2), (2, 2, 2, 3), 
(2, 2, 3, 1), (2, 2, 3, 2), (2, 2, 3, 3),
(2, 3, 1, 1), (2, 3, 1, 2), (2, 3, 1, 3), 
(2, 3, 2, 1), (2, 3, 2, 2), (2, 3, 2, 3), 
(2, 3, 3, 1), (2, 3, 3, 2), (2, 3, 3, 3), 
(3, 1, 1, 1), (3, 1, 1, 2), (3, 1, 1, 3), 
(3, 1, 2, 1), (3, 1, 2, 2), (3, 1, 2, 3), 
(3, 1, 3, 1), (3, 1, 3, 2), (3, 1, 3, 3), 
(3, 2, 1, 1), (3, 2, 1, 2), (3, 2, 1, 3), 
(3, 2, 2, 1), (3, 2, 2, 2), (3, 2, 2, 3), 
(3, 2, 3, 1), (3, 2, 3, 2), (3, 2, 3, 3), 
(3, 3, 1, 1), (3, 3, 1, 2), (3, 3, 1, 3), 
(3, 3, 2, 1), (3, 3, 2, 2), (3, 3, 2, 3), 
(3, 3, 3, 1), (3, 3, 3, 2), (3, 3, 3, 3)]

您能否更具体地说明您期望的输出?是否要返回所有可能的组合,包括带有重复的组合;还是只返回有重复的组合?@flob我需要所有可能的组合,包括有重复的组合。能否更具体地说明您期望的输出?是否要返回所有可能的组合,包括有重复的组合;或者你只知道有重复的吗?@flob我想要所有可能的组合,包括有重复的。这就是我要找的@andreihondrari非常感谢@罗里·道尔顿:我已经按照你的建议做了,谢谢!快速提问?如果没有重复,您又如何做到这一点?我只想把握两个方向@马修肯普重复了一遍,你的意思是没有(1,1)(1,1,1)。。。?为此,您需要像
结果那样使用。extend(排列(l1,i))
@matthewkemp您可以在
组合迭代器下获得这些的完整含义,这就是我要找的@andrehihondrari非常感谢@罗里·道尔顿:我已经按照你的建议做了,谢谢!快速提问?如果没有重复,您又如何做到这一点?我只想把握两个方向@马修肯普重复了一遍,你的意思是没有(1,1)(1,1,1)。。。?为此,您需要使用像
results.extend(排列(l1,i))
@matthewkemp您可以在