Python Jupyter实验室交互式绘图:不支持*:';浮动滑块';和';浮动';

Python Jupyter实验室交互式绘图:不支持*:';浮动滑块';和';浮动';,python,scipy,plotly,ipywidgets,Python,Scipy,Plotly,Ipywidgets,我正在观看一段视频,以了解如何使用plotly生成交互式绘图,但我一直遇到错误:不支持*:“FloatSlider”和“float”的操作数类型 我很确定其他部分是正确的,最初的导师做得很好,但在我的jupyter实验室,它遇到了问题 代码如下: import plotly as py import plotly.graph_objs as go import ipywidgets as widgets import numpy as np from scipy import special

我正在观看一段视频,以了解如何使用plotly生成交互式绘图,但我一直遇到错误:不支持*:“FloatSlider”和“float”的操作数类型

我很确定其他部分是正确的,最初的导师做得很好,但在我的jupyter实验室,它遇到了问题

代码如下:

import plotly as py
import plotly.graph_objs as go
import ipywidgets as widgets
import numpy as np
from scipy import special

py.offline.init_notebook_mode(connected=True)
x = np.linspace(0, np.pi, 1000)

# Then layout the graph object in plotly
# Every object starts in a new line in the layout of plotly graph_objs
layout = go.Layout(
    # The title of the layout
    title = "Simple Example of Plotly",
    # Y axis, everything goes into a dict type, same of X axis
    yaxis = dict(
        title = "volts"
    ),
    xaxis = dict(
        title = "nanoseconds"
    )
)

# Now get a function with widgets using signals and frequency
# Put the trace into the function
def update_plot(signals, frequency):

    # Get a data list to put all traces in
    data = []
    for s in signals:
        # Put traces inside the function's loop
        trace1 = go.Scatter(
            x = x,
            n = freq * x,
            # Update y value using scipy's special's bessel functions
            y = special.jv(s, n),
            # Scatter has three modes, marker, lines, marker+lines
            mode = "lines",
            # Set a name
            name = "bessel {}".format(s),
            # Set up the interpolation, how the dots are connected with lines
            # line is going to be a dict
            line = dict(
                shape = "spline"
            )
        )
        data.append(trace1)

        # Plotting also goes in the function
        fig = go.Figure(data = data, layout=layout)
        # Finally show it
        py.offline.iplot(fig)

# Once the function is done, we create the widget
# Value in signals should be a tuple
signals = widgets.SelectMultiple(options = list(range(6)), value = (0,), 
description="Bessel Order")

# Make a freq
freq = widgets.FloatSlider(min = 1, max = 20, value = 1, description="Freq")

# Finally make the interaction
widgets.interactive(update_plot, signals = signals, frequency = freq)

有人知道怎么解决吗?似乎特殊的.jv(x,y)函数不接受操作数*?但即使我创建了另一个变量n=freq*x,它仍然会报告错误。非常感谢。

当您报告Python中的错误时,您应该在问题中包含完整的回溯(即完整的错误消息)。所有输出中都有有用的信息,包括触发错误的确切行

这里,该行显示为
n=freq*x
。您将
freq
创建为
freq=widgets.FloatSlider(最小值=1,最大值=20,value=1,description=“freq”)
,因此
freq
是一个
FloatSlider
对象。另一个操作数,
x
,是一个numpy数组。显然,没有为这些操作数定义乘法运算。也就是说,Python不知道如何将
FloatSlider
和numpy数组相乘

要获取
FloatSlider
的实际值以便对其进行算术运算,请使用
value
属性。将
n=freq*x
更改为

n = freq.value * x