Python 如何从CSV文件中按升序排序列表？

这是到目前为止我的代码，我想按升序排序。我知道

reverse=True

将对我有所帮助，但我不知道如何在这里使用它

我试过：

with open('classroom1.csv') as csvfile:
    readCSV = csv.reader(csvfile)
    for row in readCSV:
        name = row[0]
        scores = [int(c) for c in row[1:]]
        total = sum(scores)

但它不起作用

---

我的列表是

[userName，score1，score2，score3]

，例如

[James，5，8，4]

如果您需要按升序排序，您不应该调用

reverse=True

如果：

classroom1.csv

：

srt = sorted(total, key=lambda x : x[1], reverse=True)
    print(name,srt)

main.py是：

Ali,100,100
Bob,50,100

您将收到：

data=[]
with open('classroom1.csv') as csvfile:
    readCSV = csv.reader(csvfile)
    for row in readCSV:
        name = row[0]
        scores = [int(c) for c in row[1:]]
        total=sum(scores)
        data.append((name,total))
srt=sorted(data, key=lambda x : x[1])
print srt

>>>

---

如果我们知道你的列表是什么样子以及应该是什么样子，那会有所帮助。所以你想要

['James'，5,4,8]

-->['James'，4,5,8]？@Stidgeon按照分数总和排序。如果没有答案，这是没有希望的。请不要诋毁你的问题。如果你想删除你的问题，请提醒版主注意。我尝试了这段代码，但没有结果。我将其中一行代码更改为f=open（'classroom1.cvs'，'a+'），因为我一直收到一个错误

[('Bob',150),('Ali',200)]

Program to short by userName with high score:
Here  is my cvs file data:

userName, score1,score2,score3
James, 7,3,8
Bob, 9,5,7
Yogi, 10,4,5

import csv
output = {}
first = True
f=open("D:\work\classroom1.cvs")
for row in csv.reader(f):
    if first:
        first = False
        continue
    key = row[0]
    row.pop(0)
    val = list(set(map(int, row)))[0]
    output[key] = val

for key in sorted(output):
    print ("%s, %s" % (key, output[key]))


Output:
>>> ================================ RESTART ================================
>>> 
Bob, 9
James, 8
Yogi, 10

Program to short by high score:
Here  is my cvs file data:

userName, score1,score2,score3
James, 7,3,8
Bob, 9,5,7
Yogi, 10,4,5
Abhi, 1,2,3

import csv
import operator
output = {}
first = True
f=open("D:\work\classroom1.cvs")
for row in csv.reader(f):
    if first:
        first = False
        continue
    key = row[0]
    row.pop(0)
    val = list(set(map(int, row)))[0]
    output[key] = val

sorted_output = sorted(output.items(), key=operator.itemgetter(1))
for key,val in sorted_output:
    print ("%s, %s" % (key, val))


Output:
>>> ================================ RESTART ================================
>>> 
Abhi, 1
Bob, 9
Yogi, 9
James, 10
>>>