如何在python中解析xml文件?
我有一个xml文件,它看起来像这样如何在python中解析xml文件?,python,xml,csv,nlp,lxml,Python,Xml,Csv,Nlp,Lxml,我有一个xml文件,它看起来像这样 <?xml version='1.0' encoding='UTF8'?> <Reviews> <Review rid="0" book_title="O-Apanhador-no-Campo-de-Centeio" score="4.0"> <sentences> <sentence id="0:0:0" place="title" polarity="neutral">
<?xml version='1.0' encoding='UTF8'?>
<Reviews>
<Review rid="0" book_title="O-Apanhador-no-Campo-de-Centeio" score="4.0">
<sentences>
<sentence id="0:0:0" place="title" polarity="neutral">
<text>Está provado:</text>
<tokens>
<word id="1" form="Está" base="estar" postag="v-fin" morf="PR 3S IND VFIN" extra="fmc * vK mv" head="0" deprel="STA" srl="PRED" obj="O" opinion="O" from="0" to="4"/>
<word id="2" form="provado" base="provar" postag="v-fin" morf="PCP M S" extra="vH jh" head="1" deprel="Cs" srl="ATR" obj="O" opinion="O" from="5" to="12"/>
<word id="3" form=":" base="--" postag="pu" morf="--" extra="--" head="0" deprel="PU" srl="" obj="O" opinion="O" from="12" to="13"/>
</tokens>
</sentence>
<sentence id="0:0:1" place="title" polarity="neutral">
<text>Pode existir um livro bom sem uma história boa.</text>
<tokens>
<word id="1" form="Pode" base="poder" postag="v-fin" morf="PR 3S IND VFIN" extra="fmc * aux" head="0" deprel="STA" srl="" obj="O" opinion="O" from="0" to="4"/>
<word id="2" form="existir" base="existir" postag="v-inf" morf="--" extra="mv" head="1" deprel="Oaux" srl="PRED" obj="O" opinion="O" from="5" to="12"/>
<word id="3" form="um" base="um" postag="pron-indef" morf="M S" extra="--" head="4" deprel="DN" srl="" obj="O" opinion="O" from="13" to="15"/>
<word id="4" form="livro" base="livro" postag="n" morf="M S" sem="sem-r" extra="--" head="1" deprel="S" srl="TH" obj="O" opinion="O" from="16" to="21"/>
<word id="5" form="bom" base="bom" postag="adj" morf="M S" extra="np-close" head="4" deprel="DN" srl="" obj="O" opinion="O" from="22" to="25"/>
<word id="6" form="sem" base="sem" postag="prp" morf="--" extra="--" head="2" deprel="fA" srl="" obj="O" opinion="O" from="26" to="29"/>
<word id="7" form="uma" base="um" postag="pron-indef" morf="F S" extra="--" head="8" deprel="DN" srl="" obj="O" opinion="O" from="30" to="33"/>
<word id="8" form="história" base="história" postag="n" morf="F S" sem="per domain sem-r" extra="--" head="6" deprel="DP" srl="COM-ADV" obj="O" opinion="O" from="34" to="42"/>
<word id="9" form="boa" base="bom" postag="adj" morf="F S" extra="jh np-close" head="8" deprel="DN" srl="" obj="O" opinion="O" from="43" to="46"/>
<word id="10" form="." base="--" postag="pu" morf="--" extra="--" head="0" deprel="PU" srl="" from="46" to="47"/>
</tokens>
其中xmlstr是xml文件内容的字符串
如何从文件中提取文本字段
注意:这是一个包含我正在使用的文件的链接
有人能帮忙吗
谢谢请尝试以下方法:
import xml.etree.ElementTree
import csv
e = xml.etree.ElementTree.parse('ReLiPalavras.xml').getroot()
with open('output1.csv', 'w') as f:
writer = csv.writer(f)
writer.writerow(('text', 'polarity'))
for sent in e.iter('sentence'):
row = sent[0].text.encode('utf-8'), sent.get('polarity')
writer.writerow(row)
然后您将在
output1.csv
文件中获得文本
元素内容和属性极性
trainset = list()
xmldoc = etree.parse('ReLiPalavras.xml')
for sentence_node in xmldoc.iter('sentence'):
sentence = list()
#for word_node in sentence_node.iter('word'):
# tag = 'O'
# if word_node.get('obj') != 'O':
# tag = 'OBJ'
sentence.append({
'sent': sentence_node[0].text,
'polarity': sentence_node.get('polarity')})
if len(sentence) != 0:
trainset.append(sentence)
这创建了一个字典列表
with open('names.csv', 'w', encoding='utf-8') as csvfile:
fieldnames = ['sent', 'polarity']
writer = csv.DictWriter(csvfile, fieldnames=fieldnames, delimiter=',')
writer.writeheader()
for d in trainset:
writer.writerow(d[0])
然后将其传递到这个csv文件中
这正是我想要的它给了我一个错误:ParseError:格式不正确(无效标记):第6行,第17列它有什么问题
with open('names.csv', 'w', encoding='utf-8') as csvfile:
fieldnames = ['sent', 'polarity']
writer = csv.DictWriter(csvfile, fieldnames=fieldnames, delimiter=',')
writer.writeheader()
for d in trainset:
writer.writerow(d[0])