当所有类都具有相似的名称时，如何在selenium python中提取数据？

我大部分的类名都是一样的，我无法提取具体的信息

 <div class="block-record-info">
    <div class="title3">Author Information</div>
    <p class="FR_field">
    <span class="FR_label">Reprint Address: </span>
    Havens, T (reprint author)
    </p>
    <table class="FR_table_noborders" rules="NONE" cellspacing="0" cellpadding="0" border="0">
    <p/>
    <p class="FR_field">
    <span class="FR_label">Addresses:   </span>
    </p>
    <table class="FR_table_noborders" rules="NONE" cellspacing="0" cellpadding="0" border="0">
    <p/>
    </div>
    <div class="block-record-info">
    <div class="title3">Publisher</div>
    <p class="FR_field">
    <value>SOC JAPANESE STUD, UNIV WASHINGTON THOMSON HALL DR-05, SEATTLE, WA 98195 USA</value>
    </p>
    </div>
    <div class="block-record-info">
    <div class="title3">Categories / Classification</div>
    <p class="FR_field">
    <span class="FR_label">Research Areas:</span>
    Area Studies; Asian Studies
    </p>
    <p class="FR_field">
    <span class="FR_label">Web of Science Categories:</span>
    Area Studies; Asian Studies
    </p>
    </div>

---

如何获得它？

您可以按照下面提到的方法获得所需的输出

代码：

# Print the "Publisher" text.
print driver.find_element_by_xpath("//div[@class='block-record-info']/div[@class='block-record-info'][1]/div").text

# Print the other paragraph text which you have specified in your output.

records = driver.find_elements_by_xpath('//div[@class="block-record-info"]/div[@class="block-record-info"]')

for record in records:
print record.find_element_by_xpath('.//p').text

---

有几次出现了

，但是您想要的那一个有特定的文本

Publisher

，因此您应该能够很容易地找到它。你试过什么？

# Print the "Publisher" text.
print driver.find_element_by_xpath("//div[@class='block-record-info']/div[@class='block-record-info'][1]/div").text

# Print the other paragraph text which you have specified in your output.

records = driver.find_elements_by_xpath('//div[@class="block-record-info"]/div[@class="block-record-info"]')

for record in records:
print record.find_element_by_xpath('.//p').text