Python 如何在PyQt5中向QLabel添加信号?
下面是PyQt4中交互式标签的代码,可以单击、右键单击和滚动。我正在转换PyQt5的代码,我代码中的很多东西现在都基于这个元素Python 如何在PyQt5中向QLabel添加信号?,python,qt,python-3.x,pyqt4,pyqt5,Python,Qt,Python 3.x,Pyqt4,Pyqt5,下面是PyQt4中交互式标签的代码,可以单击、右键单击和滚动。我正在转换PyQt5的代码,我代码中的很多东西现在都基于这个元素 class ExtendedQLabel(QLabel): def __init(self, parent): super().__init__(parent) def mousePressEvent(self, ev): if ev.button() == QtCore.Qt.RightButton:
class ExtendedQLabel(QLabel):
def __init(self, parent):
super().__init__(parent)
def mousePressEvent(self, ev):
if ev.button() == QtCore.Qt.RightButton:
self.emit(SIGNAL('rightClicked()'))
else:
self.emit(SIGNAL('clicked()'))
def wheelEvent(self, ev):
self.emit(SIGNAL('scroll(int)'), ev.delta())
如何使此PyQt5兼容 好吧,在做了很多事情之后,我明白我做错了什么:
from PyQt5 import *
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *
class ExtendedQLabel(QLabel):
def __init(self, parent):
super().__init__(parent)
clicked = pyqtSignal()
rightClicked = pyqtSignal()
def mousePressEvent(self, ev):
if ev.button() == Qt.RightButton:
self.rightClicked.emit()
else:
self.clicked.emit()
if __name__ == '__main__':
app = QApplication([])
eql = ExtendedQLabel()
eql.clicked.connect(lambda: print('clicked'))
eql.rightClicked.connect(lambda: print('rightClicked'))
eql.show()
app.exec_()
在文本clicked=pyqtSignal()
和rightClicked=pyqtSignal()
的行中,是什么将这些信号与使上述代码工作的类联系起来的?答案是正确的缩进,正确的缩进将把变量嵌套到类中,而不是随机创建一个没有用处的变量。我花了很多时间才意识到这一点,所以我认为如果有人用谷歌搜索这个,把这个留在这里可能会很有用
from PyQt5 import QtGui,QtCore,QtWidgets
class Clickable_Label(QtWidgets.QLabel):
def __init__(self):
super().__init__()
clicked = QtCore.pyqtSignal() # signal when the text entry is left clicked
def mousePressEvent(self, event):
self.clicked.emit()
QtWidgets.QLabel.mousePressEvent(self, event)
myLabel=Clickable_Label()
myLabel.setText("Clickable_Label")
myLabel.board_rule_download.clicked.connect(lambda: print('clicked'))`enter code here`