Python LXML和XSL document（）函数

嗨，我得到了以下文件：

merge.py：

from lxml import etree

xml_input = etree.XML(open('a.xml', 'r').read())
xslt_root = etree.XML(open('merge.xsl', 'r').read())
transform = etree.XSLT(xslt_root)
print str(transform(xml_input))

merge.xsl：

<xsl:stylesheet version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="/">
        <merge>
        <xsl:copy-of select="."/>
            <xsl:copy-of select="document('b.xml')"/>        
    </merge>
    </xsl:template>

---

有什么想法吗？关于我做错了什么？

您需要注册一个URI解析器。看

可能是这样（未经测试）：

---

为什么不干脆这样做呢

from lxml import etree

xml_input = etree.parse("a.xml")
xslt_root = etree.parse("merge.xsl")
transform = etree.XSLT(xslt_root)
print str(transform(xml_input))

---

更简单，不需要解析程序。

如果我使用，我得到了lxml.etree.xsltaplyerror:无法解析URIfile://b.xmlHi 弗朗西斯，谢谢你也帮了我。但是我有一个问题，如何将输出html保存为html文件？

<?xml version="1.0" encoding="ISO-8859-1"?>
<b>
 <test id="2"/>
</b>   

lxml.etree.XSLTApplyError: Cannot resolve URI string://__STRING__XSLT__/b.xml

class FileResolver(etree.Resolver):
    def resolve(self, url, pubid, context):
        return self.resolve_filename(url, context)

parser = etree.XMLParser()
parser.resolvers.add(FileResolver())
xml_input = etree.parse(open('a.xml','r'), parser)
xslt_root = etree.parse(open('merge.xsl','r'), parser)
transform = etree.XSLT(xslt_root)
print str(transform(xml_input))

from lxml import etree

xml_input = etree.parse("a.xml")
xslt_root = etree.parse("merge.xsl")
transform = etree.XSLT(xslt_root)
print str(transform(xml_input))