Python Django:编辑模型时自定义文件字段值
我有一个模型,带有Python Django:编辑模型时自定义文件字段值,python,django,file-upload,django-forms,django-file-upload,Python,Django,File Upload,Django Forms,Django File Upload,我有一个模型,带有FileField。在视图中编辑此模型时,我希望更改视图窗体中显示的FileField的“当前”值。让我解释一下 型号。py: class DemoVar_model(models.Model): ... Welcome_sound=models.FileField(upload_to='files/%Y/%m/%d') class DemoVar_addform(ModelForm): ... class Meta: mode
FileField
。在视图中编辑此模型时,我希望更改视图窗体中显示的FileField
的“当前”值。让我解释一下
型号。py:
class DemoVar_model(models.Model):
...
Welcome_sound=models.FileField(upload_to='files/%Y/%m/%d')
class DemoVar_addform(ModelForm):
...
class Meta:
model = DemoVar_model
soundform = DemoVar_addform(instance=ivrobj)
....
return render_to_response(template,{'soundform':soundform}, ....)
forms.py:
class DemoVar_model(models.Model):
...
Welcome_sound=models.FileField(upload_to='files/%Y/%m/%d')
class DemoVar_addform(ModelForm):
...
class Meta:
model = DemoVar_model
soundform = DemoVar_addform(instance=ivrobj)
....
return render_to_response(template,{'soundform':soundform}, ....)
视图。py:
class DemoVar_model(models.Model):
...
Welcome_sound=models.FileField(upload_to='files/%Y/%m/%d')
class DemoVar_addform(ModelForm):
...
class Meta:
model = DemoVar_model
soundform = DemoVar_addform(instance=ivrobj)
....
return render_to_response(template,{'soundform':soundform}, ....)
现在我想在视图中编辑此模型。当我在浏览器中查看时,我看到表单显示为
Welcome sound: Currently: welcome_files/2011/04/27/15_35_58_ojCompany.wav.mp3
Change : <Choose File button>
欢迎声音:当前:Welcome_files/2011/04/27/15_35_58_ojCompany.wav.mp3
更改:
我想更改这个“current”值,它描述了文件在我的服务器上退出时的整个路径。我想把这个字符串修剪成没有路径的文件名。如何实现这一点?一种方法是编写自定义表单小部件并覆盖呈现方法。您需要覆盖当前使用的ClearableFileInput,以更改其显示方式 下面是新的
ShortNameFileInput
的代码,它继承了默认的ClearableFileInput
,只在第19行进行了更改,仅显示文件名:
from django.forms.widgets import ClearableFileInput
import os
# missing imports
from django.utils.safestring import mark_safe
from cgi import escape
from django.utils.encoding import force_unicode
class ShortNameClarableFileInput(ClearableFileInput):
def render(self, name, value, attrs=None):
substitutions = {
'initial_text': self.initial_text,
'input_text': self.input_text,
'clear_template': '',
'clear_checkbox_label': self.clear_checkbox_label,
}
template = u'%(input)s'
substitutions['input'] = super(ClearableFileInput, self).render(name, value, attrs)
if value and hasattr(value, "url"):
template = self.template_with_initial
substitutions['initial'] = (u'<a href="%s">%s</a>'
% (escape(value.url),
escape(force_unicode(os.path.basename(value.url))))) # I just changed this line
if not self.is_required:
checkbox_name = self.clear_checkbox_name(name)
checkbox_id = self.clear_checkbox_id(checkbox_name)
substitutions['clear_checkbox_name'] = conditional_escape(checkbox_name)
substitutions['clear_checkbox_id'] = conditional_escape(checkbox_id)
substitutions['clear'] = CheckboxInput().render(checkbox_name, False, attrs={'id': checkbox_id})
substitutions['clear_template'] = self.template_with_clear % substitutions
return mark_safe(template % substitutions)
这应该可以解决问题。如果您想要一种更简单的方法,并且避免重写小部件的渲染逻辑,您可以做一些修改
from os import path
from django import forms
class FormatString(str):
def format(self, *args, **kwargs):
arguments = list(args)
arguments[1] = path.basename(arguments[1])
return super(FormatString, self).format(*arguments, **kwargs)
class ClearableFileInput(forms.ClearableFileInput):
url_markup_template = FormatString('<a href="{0}">{1}</a>')
Django 1.10.x或更早版本
最简单的方法是覆盖默认
ClearableFileInput
django小部件中的template\u substitution\u值
,该小部件稍后将用于呈现表单。这是一种更干净的方法,不会导致任何不必要的代码重复
from os import path
from django.forms.widgets import ClearableFileInput
from django.utils.html import conditional_escape
class CustomClearableFileInput(ClearableFileInput):
def get_template_substitution_values(self, value):
"""
Return value-related substitutions.
"""
return {
'initial': conditional_escape(path.basename(value.name)),
'initial_url': conditional_escape(value.url),
}
然后使用forms.py中的小部件,如下所示:
class DemoVar_addform(ModelForm):
Welcome_sound = forms.FileField(widget=CustomClearableFileInput)
...
class Meta:
model = DemoVar_model
...
Django 1.11.x或更高版本
检查。为什么我不能从FileInput派生而不是ClearableFileInput?这是一种比公认答案更干净的方法,不会导致任何不必要的代码重复。我尝试过这种方法,但“当前”没有任何修剪文件路径的情况。我在这里提出我的问题:@DhiaTN