Python “中的语法无效”;对于L";环
我有一种感觉,我在这里遗漏了一些非常简单的东西,但在这个函数中:Python “中的语法无效”;对于L";环,python,Python,我有一种感觉,我在这里遗漏了一些非常简单的东西,但在这个函数中: def triplets(perimeter): triplets, n, a, b, c = 0 #number of triplets, a, b, c, sides of a triangle, n is used to calculate a triple L = primes(int(math.sqrt(perimeter)) #list of primes to divide the perimet
def triplets(perimeter):
triplets, n, a, b, c = 0 #number of triplets, a, b, c, sides of a triangle, n is used to calculate a triple
L = primes(int(math.sqrt(perimeter)) #list of primes to divide the perimeter
for item in L: #iterate through the list of primes
if perimeter % item == 0: #check if a prime divides the perimeter
n = perimeter / item
a = n**2 - (n+1)**2 #http://en.wikipedia.org/wiki/Pythagorean_triple
b = 2n*(n+1)
c = n**2 + n**2
if a+b+c == perimeter: #check if it adds up to the perimeter of the triangle
triplets = triplets + 1
return triplets
我得到一个错误:
for item in L:
^
SyntaxError: invalid syntax
为了完整起见,我的整个程序如下所示:
import math
def primes(n): #get a list of primes below a number
if n==2: return [2]
elif n<2: return []
s=range(3,n+1,2)
mroot = n ** 0.5
half=(n+1)/2-1
i=0
m=3
while m <= mroot:
if s[i]:
j=(m*m-3)/2
s[j]=0
while j<half:
s[j]=0
j+=m
i=i+1
m=2*i+3
return [2]+[x for x in s if x]
def triplets(perimeter):
triplets, n, a, b, c = 0 #number of triplets, a, b, c, sides of a triangle, n is used to calculate a triple
L = primes(int(math.sqrt(perimeter)) #list of primes to divide the perimeter
for item in L: #iterate through the list of primes
if perimeter % item == 0: #check if a prime divides the perimeter
n = perimeter / item
a = n**2 - (n+1)**2 #http://en.wikipedia.org/wiki/Pythagorean_triple
b = 2n*(n+1)
c = n**2 + n**2
if a+b+c == perimeter: #check if it adds up to the perimeter of the triangle
triplets = triplets + 1
return triplets
def solve():
best = 0
perimeter = 0
for i in range(1, 1000):
if triplets(i) > best:
best = triplets(i)
perimeter = i
return perimeter
print solve()
导入数学
def primes(n):#获取数字下方的primes列表
如果n==2:返回[2]
elif n您在以下行之前缺少一个右括号:
L = primes(int(math.sqrt(perimeter)) #list of primes to divide the perimeter
# ^ ^ ^ ^^
#nesting count 1 2 3 21
查看如何在该行下方的“嵌套计数”中不达到0?该行前面有一个错误:
L = primes(int(math.sqrt(perimeter))
您有3个打开的括号,但只有两个关闭的括号。错误在上面一行-您缺少一个关闭括号:
L = primes(int(math.sqrt(perimeter)))
您缺少一个括号:
L = primes(int(math.sqrt(perimeter)))
^
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this one
这种情况经常发生在我身上,你只需要看看前面的线路就可以了。shot。我知道这很简单。太尴尬了。哈哈。谢谢。我想评论一下:我犯了另外两个错误(我后来发现):b=2n*(n+1)
应该是b=2*n*(n+1)
此外,我还需要以不同的方式初始化三元组,a、b、c和n。L=…
行中的括号