Python 如何打印返回的对象?
我在自定义函数中使用请求库:Python 如何打印返回的对象?,python,python-requests,Python,Python Requests,我在自定义函数中使用请求库: def add_advert(self, json_data): headers = {'Content-Type': 'application/json'} return requests.post(self.base_url + self.api_urls["add_advert"], json=json_data, headers=headers, auth=(self.ap
def add_advert(self, json_data):
headers = {'Content-Type': 'application/json'}
return requests.post(self.base_url + self.api_urls["add_advert"],
json=json_data, headers=headers,
auth=(self.api_key, ''))
response = api.add_advert(json_data=json_data)
并调用此函数:
def add_advert(self, json_data):
headers = {'Content-Type': 'application/json'}
return requests.post(self.base_url + self.api_urls["add_advert"],
json=json_data, headers=headers,
auth=(self.api_key, ''))
response = api.add_advert(json_data=json_data)
如何显示来自变量响应的内容
我尝试了:print response.content,print response.json假设要显示的内容是响应负载。。。response.text 或 response.json-.json是一个假定json负载的函数打印响应显示什么?