Python Spark:没有名为的模块*

为什么我使用

rdd=rdd.map（lambda i:Recommendation.TransfertRecurrentConfigKey（i））

时会出现此错误

    org.apache.spark.api.python.PythonException: Traceback (most recent call last):File "/usr/hdp/current/spark2-client/python/lib/pyspark.zip/pyspark/worker.py", line 161, in main
    func, profiler, deserializer, serializer = read_command(pickleSer, infile)
  File "/usr/hdp/current/spark2-client/python/lib/pyspark.zip/pyspark/worker.py", line 54, in read_command
    command = serializer._read_with_length(file)
  File "/usr/hdp/current/spark2-client/python/lib/pyspark.zip/pyspark/serializers.py", line 164, in _read_with_length
    return self.loads(obj)
  File "/usr/hdp/current/spark2-client/python/lib/pyspark.zip/pyspark/serializers.py", line 422, in loads
    return pickle.loads(obj)
ImportError: No module named Recommendation.Recommendation

当我使用这个

rdd=rdd.map（Recommendation.TransfertRecurrentConfigKey）

时，代码运行良好吗？ 如果我问这个问题，是因为我希望能够在辩论中通过关键的列表<代码>[“性别”，“年龄”，“职业”，“收入”]

编辑：我解决了错误，但我仍然不明白为什么在第一种情况下它能工作，而在第二种情况下它不能工作。 （见第二个答案）

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你是如何解决你的问题的？

class Recommendation:
@staticmethod
def TransfertRecurrentRecommendation(dataFrame):
    rdd = dataFrame.rdd.map(Recommendation.TransfertRecurrentCleanData)
    rdd = rdd.filter(lambda x: x is not None)

    #rdd = rdd.map(lambda user: ((user['Sexe'], user['Age'], user['Profession'], user['Revenus']), user['TransfertRecurrent']))
    rdd = rdd.map(lambda i: Recommendation.TransfertRecurrentConfigKey(i))
    print rdd.collect()

@staticmethod
def TransfertRecurrentConfigKey(user):
    tmp = []
    for k in ["Sexe", "Age", "Profession", "Revenus"]:
        tmp.append(user[k])
    return tuple(tmp), user['TransfertRecurrent']