如何将字符串列表中的整数转换为python中的整数？

例如，我有一个字符串列表：

lst = ["hello","ASKDJ","1","4","xcvs"]

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如何将该字符串列表中的整数转换为整数？

如果所有字符串字符都是数字，则有条件地将元素转换为整数。如果字符串的所有元素都是数字，则string方法返回true

def convert(L):
    for i, elem in enumerate(L):
        if not elem.isdigit():
            continue
        L[i] = int(elem)

In [12]: L = ["hello","ASKDJ","1","4","xcvs"]

In [13]: convert(L)

In [14]: L
Out[14]: ['hello', 'ASKDJ', 1, 4, 'xcvs']

>>> [int(elem ) if elem.isdigit() else elem for elem in lst]
['hello', 'ASKDJ', 1, 4, 'xcvs']

使用方法和步骤：

伊斯迪吉特街

如果字符串中的所有字符都是数字，则返回true 至少有一个字符，否则为false

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该列表中没有任何整数，只有字符串。可以使用int函数将一些字符串转换为整数

您将获得以下输出：

>>> 
Item hello cannot be turned into a number!
invalid literal for int() with base 10: 'hello'
Item ASKDJ cannot be turned into a number!
invalid literal for int() with base 10: 'ASKDJ'
Item xcvs cannot be turned into a number!
invalid literal for int() with base 10: 'xcvs'

现在请尝试打印列表：

>>> lst
['hello', 'ASKDJ', 1, 4, 'xcvs']

---

您真的需要为元素中的字符执行allchar.isdigit吗？《elem.isdigit》怎么了？@Abhijit:我不知道我能做到。谢谢：这样你甚至可以接受-12作为输入，因为它是一个有效的整数，即使它不包含唯一的数字。谢谢你的一个是最有用的。

>>> 
Item hello cannot be turned into a number!
invalid literal for int() with base 10: 'hello'
Item ASKDJ cannot be turned into a number!
invalid literal for int() with base 10: 'ASKDJ'
Item xcvs cannot be turned into a number!
invalid literal for int() with base 10: 'xcvs'

>>> lst
['hello', 'ASKDJ', 1, 4, 'xcvs']