Python django中request.method出现问题，它无法识别POST，而是显示GET作为请求方法

我在django for Post and Get request和一些与URL相关的安全相关的东西上做了一些实践，所以我在一个html文件中制作了一个表单，其中我使用了方法作为Post，当它进入视图模板时，它将我的方法显示为Get，我无法理解，所以请解决我的问题谢谢！我附上这篇文章的截图供你参考

代码（HTML）：-

因此，上面返回的是python代码的else部分，而不是if部分，我已经看到request.method函数将输出作为“GET”

my django应用程序中的URL:

from django.urls import path
from . import views

    urlpatterns = [
        path('', views.index, name="index"),
        path('find', views.find, name="find"),
        path('form_index/', views.form_index, name="form_index"),
        path('form_index/check/', views.check, name="check"),
    ]

我的主项目中的URL：-

"""testing URL Configuration

The `urlpatterns` list routes URLs to views. For more information please see:
    https://docs.djangoproject.com/en/3.0/topics/http/urls/
Examples:
Function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  path('', views.home, name='home')
Class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  path('', Home.as_view(), name='home')
Including another URLconf
    1. Import the include() function: from django.urls import include, path
    2. Add a URL to urlpatterns:  path('blog/', include('blog.urls'))
"""
from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include('sse.urls')),
]

---

在您的观点中，执行以下操作：

def check(request):
    if request.method == 'POST':
        return HttpResponse("This is POST request")
    else:
        return render(request, "form.html")

---

发布代码，而不是图片。共享您的URL和呈现表单的view函数Sir我已经添加了所需的代码，请再次检查我编写的代码-代码（Python）该部分呈现表单基本上它不呈现它返回httpresponseNo它不工作它将执行else块而不在if中block@Varun方法将是POST，只有在你提交表格之后

"""testing URL Configuration

The `urlpatterns` list routes URLs to views. For more information please see:
    https://docs.djangoproject.com/en/3.0/topics/http/urls/
Examples:
Function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  path('', views.home, name='home')
Class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  path('', Home.as_view(), name='home')
Including another URLconf
    1. Import the include() function: from django.urls import include, path
    2. Add a URL to urlpatterns:  path('blog/', include('blog.urls'))
"""
from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include('sse.urls')),
]

def check(request):
    if request.method == 'POST':
        return HttpResponse("This is POST request")
    else:
        return render(request, "form.html")