从Matlab用Python循环生成变量
我正在尝试将一个程序从Matlab转换为Python 我用Python写了:从Matlab用Python循环生成变量,python,loops,numpy,for-loop,if-statement,Python,Loops,Numpy,For Loop,If Statement,我正在尝试将一个程序从Matlab转换为Python 我用Python写了: age=np.arange(start_age, start_age+D, deltat) For num in age: if age[:]<(65): Y=1 break else Y=0 break break H = (1/r) * (1 - math.exp(-r * max(0, (65 - age[:]))) A = ((1 - theta)
age=np.arange(start_age, start_age+D, deltat)
For num in age:
if age[:]<(65):
Y=1
break
else
Y=0
break
break
H = (1/r) * (1 - math.exp(-r * max(0, (65 - age[:])))
A = ((1 - theta) * r - rho) / theta + 0.5 * ((1 - theta) / theta ** 2) *( _lambda **2)
g = (1/A) * (math.exp(A * (D - (age[:] - start_age))) - 1)
age=np.arange(起始年龄,起始年龄+D,延迟)
对于年龄中的num:
如果年龄[:]请尝试以下方法:
for num in age:
if num < 65:
Y=1
break
else:
Y=0
break
H = (1/r) * (1 - math.exp(-r * max(0, (65 - age[:])))
A = ((1 - theta) * r - rho) / theta + 0.5 * ((1 - theta) / theta ** 2) *(
_lambda **2)
g = (1/A) * (math.exp(A * (D - (age[:] - start_age))) - 1)# equation (A11)
年龄为num的:
如果num<65:
Y=1
打破
其他:
Y=0
打破
H=(1/r)*(1-math.exp(-r*max(0,(65-age[:]))
A=((1-θ)*r-ρ)/θ+0.5*((1-θ)/θ**2)*(
_λ**2)
g=(1/A)*(数学实验(A*(D-(年龄[:]-开始年龄))-1)#方程(A11)
如果像这样使用for循环,那么可以使用列表中的evry元素num代替age
但是:
在使用喙的方式中,如果我弄错了,你总是会在数组的第一个元素处停下来纠正我,但我不认为这是你想要的…因此,或者你失去了中断,或者你可以像这样检查第一个元素:
if age[0] < 65:
如果年龄[0]<65岁:
听起来这就是你想要的年龄和Y
:
In [314]: age = np.arange(20,80,5)
In [315]: Y = np.where(age<65, 1, 0)
In [316]: age
Out[316]: array([20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75])
In [317]: Y
Out[317]: array([1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0])
math.exp
适用于标量值,np.exp
适用于数组
通过有限的测试:
In [318]: H = (1-np.exp(max(0, 65-age)))
----------------------------------------------------------------------
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
哎呀,错了max
。这就是Python标量:
In [319]: H = (1-np.exp(np.maximum(0, 65-age)))
In [320]: H
Out[320]:
array([ -3.49342711e+19, -2.35385267e+17, -1.58601345e+15,
-1.06864746e+13, -7.20048993e+10, -4.85165194e+08,
-3.26901637e+06, -2.20254658e+04, -1.47413159e+02,
0.00000000e+00, 0.00000000e+00, 0.00000000e+00])
In [321]: g = np.exp((1-(age-20)))
In [322]: g
Out[322]:
array([ 2.71828183e+00, 1.83156389e-02, 1.23409804e-04,
8.31528719e-07, 5.60279644e-09, 3.77513454e-11,
2.54366565e-13, 1.71390843e-15, 1.15482242e-17,
7.78113224e-20, 5.24288566e-22, 3.53262857e-24])
此代码有许多问题。它没有正确缩进。它使用了几个未定义的变量。for
应该是小写。否则:
缺少冒号。为什么在else
块中有2个break
语句?而且,H
、a
和g
都不是函数,它们是使用我前面提到的未定义变量的简单表达式赋值。谢谢!我仍在学习所有这些,我确实对numpy和not numpy的不同函数感到困惑。谢谢!
In [319]: H = (1-np.exp(np.maximum(0, 65-age)))
In [320]: H
Out[320]:
array([ -3.49342711e+19, -2.35385267e+17, -1.58601345e+15,
-1.06864746e+13, -7.20048993e+10, -4.85165194e+08,
-3.26901637e+06, -2.20254658e+04, -1.47413159e+02,
0.00000000e+00, 0.00000000e+00, 0.00000000e+00])
In [321]: g = np.exp((1-(age-20)))
In [322]: g
Out[322]:
array([ 2.71828183e+00, 1.83156389e-02, 1.23409804e-04,
8.31528719e-07, 5.60279644e-09, 3.77513454e-11,
2.54366565e-13, 1.71390843e-15, 1.15482242e-17,
7.78113224e-20, 5.24288566e-22, 3.53262857e-24])