需要澄清python linkedlist中的node.next指针吗
我很难理解python中的传递值属性。在下面的代码中，需要澄清python linkedlist中的node.next指针吗,python,linked-list,deep-copy,shallow-copy,Python,Linked List,Deep Copy,Shallow Copy,我很难理解python中的传递值属性。在下面的代码中，runner正在复制current和runner。next指向给定链接列表的下一个节点，而我们将runner.next设置为runner.next.next，这对cur.next.next有何影响？runner.next和cur.next都指向同一地址吗？因为在我看来，runner只是current的一个副本，它无法访问原始cur.next。请教训我 def remove_dups_followup(ll):
runnercurrentrunner。nextrunner.nextrunner.next.nextcur.next.nextrunner.nextcur.next def remove_dups_followup(ll):
if ll.head is None:
return
current = ll.head
while current:
runner = current
while runner.next:
if runner.next.value == current.value:
runner.next = runner.next.next
else:
runner = runner.next
current = current.next
return ll.head
currentcurrentrunnercurrentrunnercurrentrunnerrunner = current