Python 由列表组成的文本文件的串联？

假设我有两个文本文件1.txt和2.txt

1.txt的内容如下：

[['Hi', 'I'], ['I'], ['_am']]

[['_a', 'good'], ['boy']]

及

2.txt的内容如下：

[['Hi', 'I'], ['I'], ['_am']]

[['_a', 'good'], ['boy']]

如何以节省时间的方式将其加入并写入新文件，例如
3.txt
，如下所示：

[['Hi', 'I'], ['I'], ['_am'], ['_a', 'good'], ['boy']]

[['Hi', 'I'], ['I'], ['_am'], ['_a', 'good'], ['boy']]

注意：我希望特殊字符（u）保持原样

我尝试了前面关于堆栈溢出的一个答案，该答案在中提到

我的尝试如下：

global inputList
inputList = []
path = "F:/Try/"
def load_data():
    for file in ['1.txt', '2.txt']:
        with open(path + file, 'r', encoding = 'utf-8) as infile:
           inputList.extend(infile.readlines())
    print(inputList)
load_data()

["[['Hi', 'I'], ['I'], ['_am']]", "[['_a', 'good'], ['boy']]"]

但是我没有得到上面所示的期望输出。我现在得到的输出如下：

global inputList
inputList = []
path = "F:/Try/"
def load_data():
    for file in ['1.txt', '2.txt']:
        with open(path + file, 'r', encoding = 'utf-8) as infile:
           inputList.extend(infile.readlines())
    print(inputList)
load_data()

["[['Hi', 'I'], ['I'], ['_am']]", "[['_a', 'good'], ['boy']]"]

为什么我的电流输出中有一个额外的（“”）

请提出一些有成效的建议

提前谢谢。
您的文件总是这样吗？然后，只需删除“外部”
[
和
]

path = "F:/Try/"

def load_data():
    result = []
    for file in ['1.txt', '2.txt']:
        with open(path + file, 'r', encoding='utf-8') as infile:
            result.append(infile.readline().strip()[1:-1])
    return "[" + ", ".join(result) + "]"

print(load_data())

哪张照片

您可能需要使用：

import json

with open("1.txt", "r") as t1, open("2.txt", "r") as t2, open("3.txt", "w") as t3:
    t3.write(json.dumps([eval(t1.read().strip()), eval(t2.read().strip())]))


3.txt

[[["Hi", "I"], ["I"], ["_am"]], [["_a", "good"], ["boy"]]]


注:





输出：

[['Hi', 'I'], ['I'], ['_am']]

就你而言：

import ast
global inputList
inputList = []
path = "F:/Try/"
def load_data():
    for file in ['1.txt', '2.txt']:
        with open(path + file, 'r', encoding = 'utf-8') as infile:
           inputList.extend(ast.literal_eval(infile.readlines()))
    print(inputList)
load_data()

试试这个（别忘了放星形操作符）：

您正在尝试从文件中读取数组。但是读取这样的文件会返回一个字符串。您必须解析字符串并将其转换为数组。这里出了很多问题。谢谢@TED。星形运算符是关于什么的？基本上，如果您有类似于[[a]]的输入，那么星形*会“展开”最外层的[]，这样我们现在就有了作为[a]的输入。谢谢Pedro。我对json不是那么精通。我将通过你的建议链接。非常感谢！