Python 在另一个函数中访问函数返回值

我有一个这样的程序，有一个StatFind类。这个类有三个方法。ncount方法返回字典列表：“finallist”。我需要将列表中的每个字典添加到mongodb数据库中

如何访问inserttomongo（）方法中的finallist

代码当前给出了一个名称错误：

s.inserttomongo(finallist)
#=> NameError: name 'finallist' is not defined

这是我的密码：

!/usr/bin/python
import pymongo,json
from datetime import date, timedelta
from collections import defaultdict
import os, sys,time,csv,glob

tsvs = glob.glob(sys.argv[1])

class StatFind:
  def __init__(self,tsvs):
    self.tsvs=tsvs

  def ncount(self, tsvs):
    if True:
      finallist=[]
      for path in tsvs:
         ....Someprocess....
         returns a list
      return finallist

  def other(self):
    samplestring= "something random"
    print samplestring

  def inserttomongo(self, finallist):
     self.finallist=ncount().finallist
     mongo=pymongo.Connection('localhost')
     mongo_db=mongo['sample']
     mongo_collection=mongo_db['users']
     for dictvalue in self.finallist:
      #  for dictvalue in ncount(tsvs):
       insert_id=mongo_collection.insert(dictvalue)

s=StatFind(tsvs)
s.ncount(tsvs)
s.other()
s.inserttomongo(finallist)

请特别阅读

您将在网上找到大量优秀的OO Python教程，如或

获取函数的返回值 例如，通过在命令行上运行python来使用解释器：

➤ python
Python 2.7.2+ (default, Jul 20 2012, 22:15:08) 
[GCC 4.6.1] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> def square(x):
...     return x*x
... 
>>> four_squared = square(4)
>>> four_squared
16

清理代码： 你的代码没有意义

什么是

nmaidcount（）.finallist

您在程序中在哪里定义

finallist

如果为真，为什么有

？永远都是这样
这就是我认为你的意思：

tsvs = glob.glob(sys.argv[1])

class StatFind:
  # This is the instance initialiser. 
  def __init__(self,tsvs):
    self.tsvs=tsvs 

    # here we define every instance of StatFind to have an attribute
    # called 'finallist' which will be accessible by all methods
    self.finallist = [] 

    # We do our initialisation here, when we initialise our object,
    # instead of in a separate method.
    for path in self.tsvs:
      finalist.append(do_something(path))

  def inserttomongo(self): 
    # The 'self' parameter is automagically set up by python to 
    # refer to the instance when 'insertmongo()' is called on an instance
    # for example, myInstance.insertmongo(), in which case 
    # self will be 'myInstance'
    mongo=pymongo.Connection('localhost')
    mongo_db=mongo['sample']
    mongo_collection=mongo_db['users']

    for dictvalue in self.finallist: 
      insert_id=mongo_collection.insert(dictvalue)

s=StatFind(tsvs) #This will call __init__() behind the scenes.
s.inserttomongo()

我猜可能对你有帮助。finallist是一个参数。您需要将一个参数传递给您的方法，如果该方法是一个标识符而不是一个常量（在您的例子中是一个名为“finallist”的标识符），则需要首先定义它！你好流程和附加到finallist是另一种方法。nmaidcount是一个输入错误，应该是ncount。我似乎仍然没有找到解决办法。请help@user1189851听起来您对Python和一般编程都是新手。我能给你的最好建议（除了亲自指导你）是运行命令行解释器（
python
在命令行上），并用它来完成教程。您还可以尝试这样的想法，即函数可以由其返回值替换。例如，如果有一个函数
def foo（x）：return x*x
，则可以用结果替换对该函数的任何调用。例如：
my_variable=foo（4）
与
my_variable=16
tsvs = glob.glob(sys.argv[1])

class StatFind:
  # This is the instance initialiser. 
  def __init__(self,tsvs):
    self.tsvs=tsvs 

    # here we define every instance of StatFind to have an attribute
    # called 'finallist' which will be accessible by all methods
    self.finallist = [] 

    # We do our initialisation here, when we initialise our object,
    # instead of in a separate method.
    for path in self.tsvs:
      finalist.append(do_something(path))

  def inserttomongo(self): 
    # The 'self' parameter is automagically set up by python to 
    # refer to the instance when 'insertmongo()' is called on an instance
    # for example, myInstance.insertmongo(), in which case 
    # self will be 'myInstance'
    mongo=pymongo.Connection('localhost')
    mongo_db=mongo['sample']
    mongo_collection=mongo_db['users']

    for dictvalue in self.finallist: 
      insert_id=mongo_collection.insert(dictvalue)

s=StatFind(tsvs) #This will call __init__() behind the scenes.
s.inserttomongo()