Python 在Django中提交post表单时出现值错误
我正在尝试为我正在构建的基于django的web应用程序制作一个提交表单。但是,当我按submit时,出现以下错误:Python 在Django中提交post表单时出现值错误,python,django,forms,Python,Django,Forms,我正在尝试为我正在构建的基于django的web应用程序制作一个提交表单。但是,当我按submit时,出现以下错误: Environment: Request Method: POST Request URL: http://127.0.0.1:8000/create Django Version: 1.10.5 Python Version: 3.6.0 Installed Applications: ['django.contrib.admin', 'django.contrib.a
Environment:
Request Method: POST
Request URL: http://127.0.0.1:8000/create
Django Version: 1.10.5
Python Version: 3.6.0
Installed Applications:
['django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'posts',
'bootstrap3']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware']
Traceback:
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/django/core/handlers/exception.py" in inner
39. response = get_response(request)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/django/core/handlers/base.py" in _get_response
187. response = self.process_exception_by_middleware(e, request)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/django/core/handlers/base.py" in _get_response
185. response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/Users/wtreston/GDrive/Django/blog/posts/views.py" in post_create
15. instance = form.save(commit=False)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/django/forms/models.py" in save
448. 'created' if self.instance._state.adding else 'changed',
Exception Type: ValueError at /create
Exception Value: The Post could not be created because the data didn't validate.
这是我创建表单的html文件:
{% extends "base.html" %}
{% block title %}Create new Post | {{ block.super}}{% endblock title %}
{% block content %}
<h1>Create Post</h1>
<form method = 'POST' action = '' class = 'form'>{% csrf_token %}
<div class="form-group">
<label for="post_title">Post Title</label>
<input class="form-control" id="post_title" placeholder="Post Title">
</div>
<div class="form-group">
<label for="post_content">Post Content</label>
<textarea class="form-control" rows="6" placeholder="Post Content"></textarea>
</div>
<!--<div class="form-group">
<label for="exampleInputFile">File input</label>
<input type="file" id="exampleInputFile">
</div>-->
<button type="submit" name="your_name" value="your_value" class="btn-link">Go</button>
</form>
{% endblock content %} %}
你知道为什么会这样吗
任何帮助都将不胜感激
谢谢 这可能有助于:-
from .forms import YourFormClass
def post_create(request):
if not request.user.is_authenticated:#If this condition is without checking POST request
return(redirect("posts:post_timeline"))
if request.method == 'POST':
form = YourFormClass(request.POST)
if form.is_valid():
instance = form.save(commit=False)
instance.save()
return(HttpResponseRedirect(instance.get_absolute_url()))
else:
#Do something
#OR
form = YourFormClass()
context = {
"form": form,
}
return render(request, "post_form.html", context)
如果form.is\u valid()
is\u valid()
是可调用的,请尝试。@不要忘记这是什么意思?您忘记了is\u valid
后面的括号。执行此操作是有效的()
@neverwalkliner我执行了此操作,现在当我单击“创建帖子”时,它刷新帖子,但不创建帖子。尝试删除if语句中的并请求.Post
。只要如果form.is_有效():
。
from .forms import YourFormClass
def post_create(request):
if not request.user.is_authenticated:#If this condition is without checking POST request
return(redirect("posts:post_timeline"))
if request.method == 'POST':
form = YourFormClass(request.POST)
if form.is_valid():
instance = form.save(commit=False)
instance.save()
return(HttpResponseRedirect(instance.get_absolute_url()))
else:
#Do something
#OR
form = YourFormClass()
context = {
"form": form,
}
return render(request, "post_form.html", context)