在Python中从json数组中提取数据对象

我有这个数据对象，我想知道如何才能选择名为

提交

（或

项目

）的子对象。我尝试了

all\u commits=all\u data['commits']

，但python迫使我给它一个整数而不是字符串。想法

 [
            {
                "commits": [
                    {
                        "project_id": "1",
                        "commit_title": "commit 1",
                        "date": "date 1",
                        "markdown": "markdown 1"
                    },
                    {
                        "project_id": "1",
                        "commit_title": "commit 2",
                        "date": "date 2",
                        "markdown": "markdown 2"
                    },
                    {
                        "project_id": "1",
                        "commit_title": "commit 3",
                        "date": "date 3",
                        "markdown": "markdown 3"
                    },
                    {
                        "project_id": "1",
                        "commit_title": "commit 4",
                        "date": "date 4",
                        "markdown": "markdown 4"
                    },
                    {
                        "project_id": "2",
                        "commit_title": "commit 5",
                        "date": "date 5",
                        "markdown": "markdown 5"
                    },
                    {
                        "project_id": "2",
                        "commit_title": "commit 6",
                        "date": "date 6",
                        "markdown": "markdown 6"
                    }
                ]
            },
            {
                "projects": [
                    {
                        "id": 1,
                        "project_name": "GreenGlass for Groups",
                        "description": "Support group projects for retention agreements"
                    },
                    {
                        "id": 2,
                        "project_name": "Zumo Redesign",
                        "description": "New eda theme-based design"
                    }
                ]
            }
        ]

---

它看起来像一个列表，请尝试：

all_commits = all_data[0]['commits']

JSON方法： 结果

---

我让它工作了，但我不相信它能扩展？如果没有一个更明显的方式，我错过了，那么我会去的。谢谢必须等9分钟broskii是讽刺和hpyerbolic，broI假设数据已经作为JSON加载。哦，我以为那是something.JSON的内容，所以我使用

JSON.loads

。

s = ''' 
PUT YOUR JSON array here
'''

import json
q = json.loads(s)
print q[0]['commits']

[{u'date': u'date 1', u'project_id': u'1', u'commit_title': u'commit 1', u'markdown': u'markdown 1'}, {u'date': u'date 2', u'project_id': u'1', u'commit_title': u'commit 2', u'markdown': u'markdown 2'}, {u'date': u'date 3', u'project_id': u'1', u'commit_title': u'commit 3', u'markdown': u'markdown 3'}, {u'date': u'date 4', u'project_id': u'1', u'commit_title': u'commit 4', u'markdown': u'markdown 4'}, {u'date': u'date 5', u'project_id': u'2', u'commit_title': u'commit 5', u'markdown': u'markdown 5'}, {u'date': u'date 6', u'project_id': u'2', u'commit_title': u'commit 6', u'markdown': u'markdown 6'}]