无法理解如何在python中解决hangman显示问题

我很难弄清楚如何在我的python刽子手游戏中显示刽子手。我当前的代码在display_word函数下的工作方式是，它将为任何一个我的hangman单词显示一个“-”。当我猜一个字母正确时，它将根据字符串中字母的数量缩短“-”显示。我想在这个显示中添加那个字母到显示中，并且仍然保留我没有猜到的字母的“-”。谁能解决这个问题

from random import choice
    
    print('Welcome to Hangman!!!, Guess the secret word ')
    
    org_word = choice(['wallee'])
    word = set(org_word)
    already_guessed = ''
    correct_letters = ''
    chances = 2
    
    def hang_man():
        while not check_win():
            guess()
    
    
    def guess():
        global chances
        global correct_letters
        global already_guessed
    
        if chances > 0:
            display_word()
            user_guess = input('\nWhat is your guess at the secret word?  ')
                #check for valid input
            if len(user_guess) > 1 or not user_guess.isalpha():
                print('you entered an invalid input and you lost a guess')
                chances -= 1
                check_loss()
                #check if letter was already guessed
            elif user_guess in already_guessed:
                print('you already entered that letter and you lost a guess')
                chances -=1
                check_loss()
                #incorrect guess
            elif user_guess not in word:
                print('\nThat guess was not in the word and you lost a guess')
                chances -= 1
                already_guessed += user_guess
                check_loss()
                #correct guess
            elif len(user_guess) == 1 and user_guess in word:
                print(f'\nGreat, your guess of {user_guess} was in the word')
                correct_letters += user_guess
                word.remove(user_guess)
    #need help here
    def display_word():
        global correct_letters
        stringed_word = (str(org_word)[:])
        for char in stringed_word:
            if char not in correct_letters:
                print(char.replace(char, '-'), end='')
    #need help here 
    
    def check_win():
        if len(word) == 0:
            print(f'Congrats, you guessed the correct word {org_word}')
            return True
    
    def check_loss():
        if chances == 0:
            print('Sorry you are out of guesses, You Lost :(')
        else:
            print(f'you now have {chances} guesses left')
    
    
    hang_man()

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我认为你让这件事变得更加困难了。对于每个字母，如果是猜测的，则打印字母，否则打印破折号。无需更换

    def display_word():
        for char in org_word:
            if char in correct_letters:
                print(char, end=' ')
            else:
                print('-', end=' ')

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伟大的解决方案，蒂姆！！