基于文本的地下城游戏python

你们能在Jupyter note中运行我的代码并告诉我它有什么问题吗？我似乎不明白为什么它不能正常工作。每次我从库存中选择商品时，它都会让我的游戏结束。我希望无论巨龙是否被击败，都能打印代码，并将打印语句发送到下一个房间

import sys

print("""Hello! Type 1 to Continue""")

#ice sword - a

#fire sword - b

#electric sword - c

inv = {'a':'Ice Sword'}

#function to display the inventory

def display():
    print("type 1 to display your inventory\n")

n = input()

if int(n)==1:

    for i in inv:

        print(i +" - "+ inv[i])

    sequence = ['c','a','b']

for i in range(0,4):

#room-1 Fire dragon - ice sword win-firesword

    if i==0:

        print("You are in room-1 a FIRE DRAGON appears\n")

display()

print("choose your Item")

x = input()

if x == 'a' and i==0:

    print("The fire dragon is defeated proceed to next room\n")
    print("You have acquired a new Item 'Fire Sword'\n")

    inv['b'] = 'Fire Sword'

else:
    print("---GAME OVER---")




#room-2 Electric dragon - ice sword win-electric sword

if i==1:

    print("You are in room-2 a ELECTRIC DRAGON appears\n")

display()

print("choose your Item")

x = input()

if x=='a' and i==1:

    print("The electric dragon is defeated you proceed next room\n")

    print("You have acquired a new Item 'Electric Sword'\n")

    inv['c'] = 'Electric Sword'

else:

    print("---GAME OVER---")



#room-3 Ice dragon - fire sword win-key

if i==2:

    print("You are in room-3 a Ice dragon appears\n")

    display()

print("choose your Item")

x = input()

if x=='b' and i==2:

    print("The Ice dragon is defeated you __ next room\n")

    print("You have acquired a new Item 'Key'\n")

    inv['d'] = 'Key'

else:

    print("---GAME OVER---")



#room-4 Dark beast Ganon specific order ([c a b])

if i==3:

    print("Use the key you won to enter the last room\n")

display()

print("choose your Item")

x = input()

if x=='d' and i==3:

    print("The Final boss DARK BEAST GANON appears\n")

else:

    print("---GAME OVER---")



#used the key and the boss appears

print("to defeat this boss you need to use a specific combination of the swords\n")

print("Enter the sequence one by one and press enter after every value")

a = []

for i in range(0,3):

    x = input()

a.append(x)

if a == sequence:

    print("Congratulation you have completed the game")



#sys.exit()



else:

    print("---GAME OVER---")

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这是一个结构糟糕的问题。我们不仅需要更多的上下文来描述正在发生的一切，而且我还建议您特别指出问题发生的代码行，在本例中，代码也用于“游戏结束”的位置

---

此外，无论它是否在Jupyter中运行，只要您使用的Python版本相同，它都将以相同的方式运行

看来您的bug是此循环的副作用：

for i in range(0,4):
    if i==0:  #room-1 Fire dragon - ice sword win-firesword
        print("You are in room-1 a FIRE DRAGON appears\n")

display()

print("choose your Item")
x = input()
if x == 'a' and i==0:

请注意，即使仅在

i==0

时打印，循环仍然通过

i=1

、

i=2

和

i=3

执行。我突出显示的最后一行，

如果x='a'和I==0:

，则计算结果为False，因为此时

I==0

为False-

I

为

3

（因为循环已完成）