Python Can'；t将数字连接到变量

我试图在变量中添加一个数字，但它不起作用。我也尝试过使用“.”运算符而不是“+”，但这不起作用。我甚至试过不用+或。（工作表索引）而这也不起作用。有点困在这里了-非常感谢你的帮助

代码如下：

workbook = xlsxwriter.Workbook('JAY_test.xlsx')
worksheet0 = workbook.add_worksheet('Toys Ordered')
worksheet1 = workbook.add_worksheet('Toys Shipped')

for index in range(len(case_queries)):
    cur.execute(case_queries[index])
    rows = cur.fetchall()

    # Start from the first cell. Rows and columns are zero indexed.
    row = 0
    col = 0

    # Iterate over the data and write it out row by row.
    for return_date, return_hour, return_count in (rows):
        worksheet+index.write(row, col,     str(return_date))
        worksheet+index.write(row, col + 1, return_hour)
        workshweet+index.write(row, col + 2, return_count)
        row += 1

我收到的错误如下：

Traceback (most recent call last):
  File "test.py", line 38, in <module>
    worksheet+index.write(row, col,     str(return_date))
NameError: name 'worksheet' is not defined
Exception Exception: Exception('Exception caught in workbook destructor. Explicit close() may be required for workbook.',) in <bound method Workbook.__del__ of <xlsxwriter.workbook.Workbook object at 0x2173c10>> ignored

回溯（最近一次呼叫最后一次）：
文件“test.py”，第38行，在
工作表+索引。写入（行、列、str（返回日期））
名称错误：未定义名称“工作表”
异常异常：忽略中的异常（“工作簿析构函数中捕获的异常。工作簿可能需要显式关闭（）”，）

这种命名方法行不通。你应该改用

---

您似乎对名称在python中的工作方式感到困惑<代码>工作表+索引不是访问

工作表0

的方式。显然，这就是我问这个问题的原因。

workbook = xlsxwriter.Workbook('JAY_test.xlsx')
worksheet = []
worksheet.append(workbook.add_worksheet('Toys Ordered')) # worksheet[0]
worksheet.append(workbook.add_worksheet('Toys Shipped')) # worksheet[1]

for index in range(len(case_queries)):
    cur.execute(case_queries[index])
    rows = cur.fetchall()

    # Start from the first cell. Rows and columns are zero indexed.
    row = 0
    col = 0

    # Iterate over the data and write it out row by row.
    for return_date, return_hour, return_count in (rows):
        worksheet[index].write(row, col,     str(return_date))
        worksheet[index].write(row, col + 1, return_hour)
        worksheet[index].write(row, col + 2, return_count)
        row += 1