Python 调用方法时获取有关参数的错误
我试图从中获取电子邮件的功能文件:Python 调用方法时获取有关参数的错误,python,python-behave,Python,Python Behave,我试图从中获取电子邮件的功能文件: Scenario: Login to website Given I navigate to Login page When I click on login button Then I redirected to login page Then I enter valid "<Email>" | Email | | test | When I click on Submit 当我将上
Scenario: Login to website
Given I navigate to Login page
When I click on login button
Then I redirected to login page
Then I enter valid "<Email>"
| Email |
| test |
When I click on Submit
当我将上述方法分步骤调用时:
from Base.BasePage import BasePage
from behave import step, Given, When, Then
from Pages.LoginPage import loginpage
@Given('I navigate to Login page')
def step_impl(Context):
BasePage.load_BaseURL();
@When('I click on login button')
def step_impl(Context):
loginpage.clickLoginLink()
@Then('I redirected to login page')
def step_impl(self):
print('Verifying user logged in..')
@Then('I enter valid "{Email}"')
def step_impl(Email):
loginpage.enterEmail(Email);
我有以下错误:
我尝试添加带有参数的**,但没有成功。您正在调用
enterEmail
作为loginpage.enterEmail(上下文,电子邮件)
这里您将参数传递给方法,如下所示
如果可行,请尝试删除登录页面或上下文。它应该是一个实例方法吗?您的3个参数是
loginpage
,context
和Email
这是否回答了您的问题?“它不工作”不是一个描述。真的帮不上什么忙了,因为正如我在第一条评论中所说的,不清楚你的函数属于什么,也不清楚这3个参数来自何处仍然不清楚登录页面是什么is@HelpingHands那么为什么它的名字包含大写字母呢?
from Base.BasePage import BasePage
from behave import step, Given, When, Then
from Pages.LoginPage import loginpage
@Given('I navigate to Login page')
def step_impl(Context):
BasePage.load_BaseURL();
@When('I click on login button')
def step_impl(Context):
loginpage.clickLoginLink()
@Then('I redirected to login page')
def step_impl(self):
print('Verifying user logged in..')
@Then('I enter valid "{Email}"')
def step_impl(Email):
loginpage.enterEmail(Email);
File "..\steps\Steps_Login.py", line 27, in step_impl
loginpage.enterEmail(context, Email);
TypeError: enterEmail() takes 1 positional argument but 3 were given