在python中以行格式显示整数

我在想办法让这些整数按行显示，同时保持它们的顺序

但是当我运行代码时，我得到的是显示

Enter numbers 1... 22,34,35,40,55
Enter numbers 2... 12,14,34,47,49
Enter numbers 3... 1,4,10,19,30

Section 1             #
The number seqeuce is 0 between 0 and 9
The number seqeuce is 0 between 10 and 19
The number seqeuce is 1 between 20 and 29
The number seqeuce is 2 between 30 and 39
The number seqeuce is 1 between 40 and 49
The number seqeuce is 1 between 50 and 59
Section 2
The number seqeuce is 0 between 0 and 9
The number seqeuce is 2 between 10 and 19
The number seqeuce is 0 between 20 and 29
The number seqeuce is 1 between 30 and 39
The number seqeuce is 2 between 40 and 49
The number seqeuce is 0 between 50 and 59
Section 3
The number seqeuce is 2 between 0 and 9
The number seqeuce is 2 between 10 and 19
The number seqeuce is 0 between 20 and 29
The number seqeuce is 1 between 30 and 39
The number seqeuce is 0 between 40 and 49
The number seqeuce is 0 between 50 and 59
                      #

这就是我希望看到的秩序 对应于范围整数

Enter numbers 1... 22,34,35,40,55
Enter numbers 2... 12,14,34,47,49
Enter numbers 3... 1,4,10,19,30
Section 1
The number seqeuce is 0 0 1 2 1 1 #
Section 2                         #
The number seqeuce is 0 2 0 1 2 0 # <-- Here is the sequennce from above
Section 3                         #
The number seqeuce is 2 2 0 1 0 0 #

---

简单的重新安排：

print "The number sequence is",
for bin_tens in bin_range:
    print group_counter[bin_tens],
print

---

这是以colunm格式打印出来的，我想它会逐个分解每个整数。@Howie注意

打印的
末尾的
，
。它可以防止
打印
追加换行符。这与已在使用的代码相同。这将如何使它变得更好，或者是我所要求的。@Howie:这不是你说的你正在使用的代码，它以你所要求的格式生成数字。当您使用它而不是您的
用于bin\u范围内的bin\u tens:
循环时，它为您产生了什么？对不起。这正好行得通。还是有点困惑，但我会解决的。
print "The number sequence is",
for bin_tens in bin_range:
    print group_counter[bin_tens],
print