在python数组中移动行和列

我正在构建一个基本的映射机器人，所有数据都存储在一个2D python数组中。但是，我无法找到任何方法来移动整行或整列，然后在其中插入空白行/列。例如：

['#','0','0']        
['0','1','0']                                            
['#','0','0']

如果移动到右侧，看起来像：

['0','#','0']        
['0','0','1']                                            
['0','#','0']

['0','0','0']         
['#','0','#']                                     
['0','1','0']

或

如果向下移动，看起来像：

['0','#','0']        
['0','0','1']                                            
['0','#','0']

['0','0','0']         
['#','0','#']                                     
['0','1','0']

我已经知道了当在预定义数组之外检测到某些东西时如何扩展数组，但是我无法像上面演示的那样移动行和列

---

任何帮助都将不胜感激。谢谢：）

你看过numpy和numpy.roll了吗

import numpy as np
a = np.array([['#','0','0'],
['0','1','0'],                                           
['#','0','0']])

然后你可以右转：

a = np.roll(a,1)
a[:,0] = 0

左移：

a = np.roll(a,-1)
a[:,-1] = 0

上移：

a = np.roll(a,-1,axis = 0)
a[-1,:] = 0

下移：

a = np.roll(a,1,axis = 0)
a[0,:] = 0

---

您可以创建一个类来处理这种移动，如下所示：

class Board(object):
    def __init__(self, rows):
        self.rows = rows
        self.print_status()

    def print_status(self):
        for row in self.rows:
            print(row)

    def right(self):
        new_rows = []
        for row in self.rows:
            row = row[-1:] + row[:len(row)-1]
            new_rows.append(row)
        self.rows = new_rows
        self.print_status()

    def left(self):
        new_rows = []
        for row in self.rows:
            row = row[1:] + row[:1]
            new_rows.append(row)
        self.rows = new_rows
        self.print_status()

    def up(self):
        new_rows = []
        for row in self.rows[1:]:
            new_rows.append(row)
        new_rows.append(self.rows[0])
        self.rows = new_rows
        self.print_status()

    def down(self):
        new_rows = []
        new_rows.append(self.rows[-1])
        for row in self.rows[:-1]:
            new_rows.append(row)
        self.rows = new_rows
        self.print_status()

例如：

>>> a = Board([[1,2,3],[4,5,6],[7,8,9]])
[1, 2, 3]
[4, 5, 6]
[7, 8, 9]

>>> a.down()
[7, 8, 9]
[1, 2, 3]
[4, 5, 6]

>>> a.up()
[1, 2, 3]
[4, 5, 6]
[7, 8, 9]

>>> a.right()
[3, 1, 2]
[6, 4, 5]
[9, 7, 8]

---

这可以通过numpy的“滚动”功能轻松完成
您的例子：

import numpy as np
a = np.array([['#','0','0'], ['0','1','0'], ['#','0','0']])

输出将是：

array([['#', '0', '0'],
   ['0', '1', '0'],
   ['#', '0', '0']], dtype='<U1')

输出将是

array([['0', '#', '0'],
   ['0', '0', '1'],
   ['0', '#', '0']], dtype='<U1')

产量将是

array([['#', '0', '#'],
   ['0', '1', '0'],
   ['0', '0', '0']], dtype='<U1')

输出

array([['0', '0', '0'],
   ['#', '0', '#'],
   ['0', '1', '0']], dtype='<U1')

数组（[['0'，0'，0']，
['#', '0', '#'],
['0'，'1'，'0']]，dtype='numpy解决方案工作得很好，但是这里有一个纯Python的解决方案，没有导入。请注意，大多数代码只打印结果——每卷只使用一行代码。我还添加了
shiftedup
，其中矩阵向上旋转，最后一行替换为全零（尽管这样做效率更高）

该文件的打印输出为：

Original:
[1, 2, 3]
[4, 5, 6]
[7, 8, 9]

Rolled up:
[4, 5, 6]
[7, 8, 9]
[1, 2, 3]

Rolled down:
[7, 8, 9]
[1, 2, 3]
[4, 5, 6]

Rolled left:
[2, 3, 1]
[5, 6, 4]
[8, 9, 7]

Rolled right:
[3, 1, 2]
[6, 4, 5]
[9, 7, 8]

Shifted up:
[4, 5, 6]
[7, 8, 9]
[0, 0, 0]

roll本身并不会插入空行，它只是从数组的另一侧获取。您知道有没有这样一种方法：将顶部的数字替换为底部的数字，然后替换为一行零。例如：[1,2,3][4,5,6][7,8,9]变为[4,5,6][7,8,9][0,0,0]@user9015687:查看我的代码和打印输出中的添加内容。谢谢，这非常有效。我对使用冒号操纵数组有点困惑，我到处都看到过冒号，但我不太理解它们。你不能告诉我它们是什么意思，可以吗。Thanks@user9015687：这是Python的切片表示法如果您仍然不理解切片，请在“python切片”上进行web搜索。这些解释比我更好。
array([['0', '0', '0'],
   ['#', '0', '#'],
   ['0', '1', '0']], dtype='<U1')

myarray = [
    [1, 2, 3],
    [4, 5, 6],
    [7, 8, 9],
]
print('\nOriginal:')
for row in myarray:
    print(row)

rolledup = myarray[1:] + myarray[:1]
print('\nRolled up:')
for row in rolledup:
    print(row)

rolleddown = myarray[-1:] + myarray[:-1]
print('\nRolled down:')
for row in rolleddown:
    print(row)

rolledleft = [row[1:] + row[:1] for row in myarray]
print('\nRolled left:')
for row in rolledleft:
    print(row)

rolledright = [row[-1:] + row[:-1] for row in myarray]
print('\nRolled right:')
for row in rolledright:
    print(row)

shiftedup= myarray[1:] + [[0] * len(myarray[0])]
print('\nShifted up:')
for row in shiftedup:
    print(row)

Original:
[1, 2, 3]
[4, 5, 6]
[7, 8, 9]

Rolled up:
[4, 5, 6]
[7, 8, 9]
[1, 2, 3]

Rolled down:
[7, 8, 9]
[1, 2, 3]
[4, 5, 6]

Rolled left:
[2, 3, 1]
[5, 6, 4]
[8, 9, 7]

Rolled right:
[3, 1, 2]
[6, 4, 5]
[9, 7, 8]

Shifted up:
[4, 5, 6]
[7, 8, 9]
[0, 0, 0]