如何使用python difflib将json对象与多个字段进行比较

理想的结果是JSON对象看起来与下面的示例类似。从那里，difflib将处理DataToCompare name和address到DataSetAgainst name和address，并给出与JSON out示例类似的差异

JSON格式：

{
  "DataToCompare": [
    {
        "name": "Alex Young",
        "address": "123 Main Street"
    }
  ],
  "DataSetAgainst": [
    {
        "name": "Bob Doll",
        "address": "555 South Street"
    },
    {
        "name": "Bob Young",
        "adress": "123 Main St."
    }
  ]
}

JSON输出：

[
    {
        "name": "Bob Doll",
        "Name Match": 11.8,
        "address": "555 South Street",
        "address match": <some number>
    },
    {
        "name": "Bob Young",
        "Name Match": 55.6,
        "address": "123 Main St.",
        "address match": <some number>
    }
]

Basic将您的差异部分放入函数中，例如

diff（key）：

和do

用于输入['name'，'address']：；差异=差异（键）

。顺便说一句：你在比较123大街、555南街，第二个是用

清理的。isalnum（）

第一个不是！

data_to_compare = dataIncoming["DataToCompare"][0]
mt_name = data_to_compare['name']

dataList = []
for i in dataIncoming["DataSetAgainst"]:
    dataList.append(i["name"])

dataResults = []

for i in dataList:
    dataBack = {}
    clean_name = ''.join(e for e in i if e.isalnum())
    sequence = difflib.SequenceMatcher(isjunk=None, a=mt_name, b=clean_name)
    difference = sequence.ratio()*100
    difference = round(difference, 1)

    dataBack["name"] = i
    dataBack["Name Match"] = difference

    dataResults.append(dataBack)

return json.dumps(dataResults)