Python 如何正确部署我的flask应用程序？

我原来的应用程序是这样的（这里不需要以前的路线）：

python文件本身被称为

app.py

现在要在heroku上部署我的应用程序，我添加了一个文件

Procfile

文件，其中包含以下句子：

web:gunicorn app:app

并在以前共享的代码行中添加了以下内容：

app = Flask(__name__)

@app.route('/')
#if __name__ == "__main__" :
def index():
    parser = argparse.ArgumentParser()
    parser.add_argument('dir', type=str, help='specify the images directory')

我在网页上看到的错误是：

Application error
An error occurred in the application and your page could not be served. If you are the application owner, check your logs for details.

调试显示：

2018-07-11T12:03:06.041871+00:00 app[web.1]: [2018-07-11 12:03:06 +0000] [9] [ERROR] Exception in worker process
2018-07-11T12:03:06.035624+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/app/wsgiapp.py", line 41, in load_wsgiapp
2018-07-11T12:03:06.035631+00:00 app[web.1]: if __name__ == "__main__" :
2018-07-11T12:03:06.035639+00:00 app[web.1]: SyntaxError: invalid syntax
2018-07-11T12:03:06.041875+00:00 app[web.1]: Traceback (most recent call last):
2018-07-11T12:03:06.041877+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/arbiter.py", line 583, in spawn_worker
2018-07-11T12:03:06.041879+00:00 app[web.1]: worker.init_process()
2018-07-11T12:03:06.041881+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/workers/base.py", line 129, in init_process
2018-07-11T12:03:06.041882+00:00 app[web.1]: self.load_wsgi()
2018-07-11T12:03:06.041884+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/workers/base.py", line 138, in load_wsgi
2018-07-11T12:03:06.041885+00:00 app[web.1]: self.wsgi = self.app.wsgi()
2018-07-11T12:03:06.041887+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/app/base.py", line 67, in wsgi
2018-07-11T12:03:06.041889+00:00 app[web.1]: self.callable = self.load()
2018-07-11T12:03:06.041892+00:00 app[web.1]: return self.load_wsgiapp()
2018-07-11T12:03:06.041894+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/app/wsgiapp.py", line 41, in load_wsgiapp
2018-07-11T12:03:06.041890+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/app/wsgiapp.py", line 52, in load
2018-07-11T12:03:06.041895+00:00 app[web.1]: return util.import_app(self.app_uri)
2018-07-11T12:03:06.041897+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.6/site-packages/gunicorn/util.py", line 350, in import_app
2018-07-11T12:03:06.041898+00:00 app[web.1]: __import__(module)
2018-07-11T12:03:06.041900+00:00 app[web.1]: File "/app/app.py", line 121
2018-07-11T12:03:06.041901+00:00 app[web.1]: if __name__ == "__main__" :
2018-07-11T12:03:06.041903+00:00 app[web.1]: ^
2018-07-11T12:03:06.041910+00:00 app[web.1]: SyntaxError: invalid syntax
2018-07-11T12:03:06.042123+00:00 app[web.1]: [2018-07-11 12:03:06 +0000] [9] [INFO] Worker exiting (pid: 9)
2018-07-11T12:03:06.201688+00:00 app[web.1]: [2018-07-11 12:03:06 +0000] [4] [INFO] Shutting down: Master
2018-07-11T12:03:06.202039+00:00 app[web.1]: [2018-07-11 12:03:06 +0000] [4] [INFO] Reason: Worker failed to boot.
2018-07-11T12:03:06.328723+00:00 heroku[web.1]: Process exited with status 3

其中最重要的一行是

原因：Worker无法启动

，这让我觉得我没有正确启动应用程序。有人能引导我去那里吗（它指向以if开头的那行，但它对我来说没有意义，因为它被注释了）

---

即使在完全删除包含if的行并按下后，我仍然会得到一个与之相关的错误。

检查此样板文件是否可以帮助您

import argparse
from flask import Flask


def create_app(config=None):
    app = Flask(__name__)

    app.config.update(dict(DEBUG=True))
    app.config.update(config or {})

    # Definition of the routes. Put them into their own file. See also
    # Flask Blueprints: http://flask.pocoo.org/docs/latest/blueprints
    @app.route("/")
    def hello_world():
        return "Hello World"

    return app


if __name__ == "__main__":
    parser = argparse.ArgumentParser()
    parser.add_argument('dir', type=str, help='specify the images directory')
    parser.add_argument("-p", "--port", action="store", default="8000")

    args = parser.parse_args()
    port = int(args.port)
    app = create_app()
    app.run(host="0.0.0.0", port=port)

---

运行app.run的位置？app.run是什么意思？app.py？初始化flask应用程序（

app=flask（\uuu name\uuu）

）。现在我的问题是，您在哪里添加了启动flask Apphave的

app.run（）

命令？实际上，我所遵循的教程没有该步骤

import argparse
from flask import Flask


def create_app(config=None):
    app = Flask(__name__)

    app.config.update(dict(DEBUG=True))
    app.config.update(config or {})

    # Definition of the routes. Put them into their own file. See also
    # Flask Blueprints: http://flask.pocoo.org/docs/latest/blueprints
    @app.route("/")
    def hello_world():
        return "Hello World"

    return app


if __name__ == "__main__":
    parser = argparse.ArgumentParser()
    parser.add_argument('dir', type=str, help='specify the images directory')
    parser.add_argument("-p", "--port", action="store", default="8000")

    args = parser.parse_args()
    port = int(args.port)
    app = create_app()
    app.run(host="0.0.0.0", port=port)