Python稀疏矩阵是否删除除一个之外的重复索引?
我在计算向量矩阵之间的余弦相似性,得到的结果是稀疏矩阵,如下所示:Python稀疏矩阵是否删除除一个之外的重复索引?,python,matrix,scipy,sparse-matrix,Python,Matrix,Scipy,Sparse Matrix,我在计算向量矩阵之间的余弦相似性,得到的结果是稀疏矩阵,如下所示: (0,26)0.359171459261 (0,25)0.121145761751 (0,24)0.316922015914 (0,23)0.15762038039 (0,22)0.636466644041 (0,21)0.136216495731 (0,20)0.243164535496 (0,19)0.348272617805 (0,18)0.636466644041 (0,17)1.0 但也有重复的情况,例如: (0,
- (0,26)0.359171459261
- (0,25)0.121145761751
- (0,24)0.316922015914
- (0,23)0.15762038039
- (0,22)0.636466644041
- (0,21)0.136216495731
- (0,20)0.243164535496
- (0,19)0.348272617805
- (0,18)0.636466644041
- (0,17)1.0
vectorized_words = sparse.csr_matrix(vectorize_words(nostopwords,glove_dict))
cos_similiarity = cosine_similarity(vectorized_words,dense_output=False)
总之,我不想删除所有的重复项,我想用pythonic的方法只剩下其中一个
提前谢谢你 我认为最容易得到
coo
格式矩阵的上三角:
首先制作一个小的对称矩阵:
In [876]: A = sparse.random(5,5,.3,'csr')
In [877]: A = A+A.T
In [878]: A
Out[878]:
<5x5 sparse matrix of type '<class 'numpy.float64'>'
with 11 stored elements in Compressed Sparse Row format>
In [879]: A.A
Out[879]:
array([[ 0. , 0. , 0.81388978, 0. , 0. ],
[ 0. , 0. , 0.73944395, 0.20736975, 0.98968617],
[ 0.81388978, 0.73944395, 0. , 0. , 0. ],
[ 0. , 0.20736975, 0. , 0.05581152, 0.04448881],
[ 0. , 0.98968617, 0. , 0.04448881, 0. ]])
转换回0,并使用消除0
修剪矩阵
In [890]: A1 = Ao.tocsr()
In [891]: A1
Out[891]:
<5x5 sparse matrix of type '<class 'numpy.float64'>'
with 11 stored elements in Compressed Sparse Row format>
In [892]: A1.eliminate_zeros()
In [893]: A1
Out[893]:
<5x5 sparse matrix of type '<class 'numpy.float64'>'
with 6 stored elements in Compressed Sparse Row format>
In [894]: A1.A
Out[894]:
array([[ 0. , 0. , 0.81388978, 0. , 0. ],
[ 0. , 0. , 0.73944395, 0.20736975, 0.98968617],
[ 0. , 0. , 0. , 0. , 0. ],
[ 0. , 0. , 0. , 0.05581152, 0.04448881],
[ 0. , 0. , 0. , 0. , 0. ]])
不使用Ao.data[mask]=0您可以将此代码作为仅消除较低三角形值的模型。将单词矢量化和余弦相似性从何而来?生成
cos\u相似度时删除“重复项”可能比生成后从矩阵中删除“重复项”更容易<代码>稀疏
矩阵不是为单个元素操作而设计的。scipy.spatial.distance.squareform
转换为消除重复的紧凑上三角形式。我不知道是否有一个版本可以处理稀疏矩阵。@hpaulj cosine\u相似度来自sklearn,矢量化单词是我的功能,让每个单词矢量不会“消除零”删除所有零?我的意思是,我可能在某个地方有一个来自原始矩阵的0值,它也会删除它?是的,它会。我将为coo
消除零
添加代码,以防您想将其调整为直接使用掩码
。非常感谢
In [890]: A1 = Ao.tocsr()
In [891]: A1
Out[891]:
<5x5 sparse matrix of type '<class 'numpy.float64'>'
with 11 stored elements in Compressed Sparse Row format>
In [892]: A1.eliminate_zeros()
In [893]: A1
Out[893]:
<5x5 sparse matrix of type '<class 'numpy.float64'>'
with 6 stored elements in Compressed Sparse Row format>
In [894]: A1.A
Out[894]:
array([[ 0. , 0. , 0.81388978, 0. , 0. ],
[ 0. , 0. , 0.73944395, 0.20736975, 0.98968617],
[ 0. , 0. , 0. , 0. , 0. ],
[ 0. , 0. , 0. , 0.05581152, 0.04448881],
[ 0. , 0. , 0. , 0. , 0. ]])
def eliminate_zeros(self):
"""Remove zero entries from the matrix
This is an *in place* operation
"""
mask = self.data != 0
self.data = self.data[mask]
self.row = self.row[mask]
self.col = self.col[mask]