Python matplotlib：连接两个子图

我试图创建一个x轴断裂的图表。我使用了matplotlib页面上的示例

我的问题是：如何连接这两个图？我需要一条闭合线来绘制图形（两个x轴应该更接近）

有办法得到这个吗

import matplotlib.pyplot as plt

#x-axis
x_axis = [0,1,2,3,4,5,6,7,8,19,20,21,22,23,24,25]

# Line 1
line = [99,91,86,80,80,76,72,72,73,74,76,78,79,80,80,80]


# create broken x-axis
f, (ax, ax2) = plt.subplots(1, 2, sharey=True)
ax.step(x_axis, line, color='red')
ax2.step(x_axis, line, color='red')

ax.set_xlim(0, 10.5)
ax2.set_xlim(18.5, 30)

ax.spines['right'].set_visible(False)
ax.spines['top'].set_visible(False)

ax2.spines['left'].set_visible(False)
ax2.spines['top'].set_visible(False)
ax2.spines['right'].set_visible(False)

ax2.tick_params(
                axis='y',
                which='both',
                left='off')

# seperators for x-axis

d = .015
kwargs = dict(transform=ax.transAxes, color='k', clip_on=False)
ax.plot((1 - d, 1 + d), (-d, +d), **kwargs) 

kwargs.update(transform=ax2.transAxes) 
ax2.plot ( (0-d ,0+d),(-d, +d ), **kwargs)

plt.show()

有没有办法得到“一”图

---

您可以在

图形

对象上使用

行

。 其优点是，这些图形线的级别高于轴上的图形线，因此无需为其绘制轴。 （我从这个答案中得到了这个想法：）

应用于您的代码，如下所示：

import matplotlib.pyplot as plt
import matplotlib as mpl

#x-axis
x_axis = [0,1,2,3,4,5,6,7,8,19,20,21,22,23,24,25]

# Line 1
line = [99,91,86,80,80,76,72,72,73,74,76,78,79,80,80,80]


# create broken x-axis
f, (ax, ax2) = plt.subplots(1, 2, sharey=True)
ax.step(x_axis, line, color='red')
ax2.step(x_axis, line, color='red')

ax.set_xlim(0, 10.5)
ax2.set_xlim(18.5, 30)

ax.spines['right'].set_visible(False)
ax.spines['top'].set_visible(False)

ax2.spines['left'].set_visible(False)
ax2.spines['top'].set_visible(False)
ax2.spines['right'].set_visible(False)

ax2.tick_params(
                axis='y',
                which='both',
                left='off')

# seperators for x-axis

d = .015
kwargs = dict(transform=ax.transAxes, color='k', clip_on=False)
ax.plot((1 - d, 1 + d), (-d, +d), **kwargs) 

kwargs.update(transform=ax2.transAxes) 
ax2.plot ( (0-d ,0+d),(-d, +d ), **kwargs)

# transFigure: used to transform the coordinates from your subplots
# to coordinates on the figure
# points are hardcoded as an example
transFigure = f.transFigure.inverted()
# last point on your left figure
coord1 = transFigure.transform(ax.transData.transform([8,74]))
# first point on your right figure
coord2 = transFigure.transform(ax2.transData.transform([19,74]))

# generate your line with the transformed coordinates
line = mpl.lines.Line2D((coord1[0],coord2[0]),(coord1[1],coord2[1]),
                       transform=f.transFigure, color='red')
# add your line to the figure
f.lines.append(line)

plt.show()

---

我在这里定义的

connect\u spines

功能可能是一个起点：