在Python中对嵌套字典中的键和值进行排序并按顺序打印

这是我的第一个问题。我正在学习如何用Python操作字典。但我面临着一个挑战

我有一本嵌套的足球比赛词典。每个子词典都是一场比赛，两支球队和相应数量的进球。 我需要打印每场比赛的结果，按字母顺序对每个队进行排序。此外，下一步是打印以下结果

比赛，但也包括上一场比赛的结果，保持所有球队按字母顺序排序

以下是一个例子：

soccer = {
    1 : {"England": 2, "Poland": 3},
    2 : {"Italy": 2, "Sweeden": 0},
    3 : {"Spain": 2, "Belgium": 2}
}

输出应如下所示：

Points Scored After Match 1

England: 0 points
Poland: 3 points


Points Scored After Match 2

England: 0 points
Italy: 3 points
Poland: 3 points
Sweeden: 0 points


Points Scored After Match 3

Belgium: 1 point
England: 0 points
Italy: 3 points
Poland: 3 points
Spain: 1 point
Sweeden: 0 points

---

提前感谢。

您可以使用此示例来对字典中的键/值进行排序，并为打印功能设置项目格式：

soccer={1:{"England":2,"Poland":3}, 2:{"Italy":2, "Sweeden":0}, 3:{"Spain":2, "Belgium":2}}

points = {}
for match_no, match in sorted(soccer.items(), key=lambda k: k[0]):
    team_1, team_2 = match.keys()
    score_1, score_2 = match.values()

    if score_1 == score_2:
        points[team_1] = points.get(team_1, 0) + 1
        points[team_2] = points.get(team_2, 0) + 1
    elif score_1 > score_2:
        points[team_1] = points.get(team_1, 0) + 3
        points[team_2] = points.get(team_2, 0) + 0
    else:
        points[team_1] = points.get(team_1, 0) + 0
        points[team_2] = points.get(team_2, 0) + 3

    # print results:
    print()
    print('Points Scored After Match {}'.format(match_no))
    print()

    for team, p in sorted(points.items(), key=lambda k: k[0]):
        print('{}: {} point{}'.format(team, p, '' if p == 1 else 's'))

印刷品：

Points Scored After Match 1

England: 0 points
Poland: 3 points

Points Scored After Match 2

England: 0 points
Italy: 3 points
Poland: 3 points
Sweeden: 0 points

Points Scored After Match 3

Belgium: 1 point
England: 0 points
Italy: 3 points
Poland: 3 points
Spain: 1 point
Sweeden: 0 points

这应该做到：

soccer={1:{"England":2,"Poland":3}, 2:{"Italy":2, "Sweeden":0}, 3:{"Spain":2, "Belgium":2}}
points={"England":0,"Poland":0,"Italy":0, "Sweeden":0,"Spain":0, "Belgium":0}
for match_number in soccer:
    for country in soccer[match_number]:
        team_one, team_two = soccer[match_number].keys()
        score_one, score_two = soccer[match_number].values()
        if score_one > score_two:
            points[team_one] = points.get(team_one) + 3
        if score_one < score_two:
            points[team_two] = points.get(team_two) + 3
        if score_one == score_two:
            points[team_one] = points.get(team_one) + 1
            points[team_two] = points.get(team_two) + 1
        print("Points scored after: ", match_number)
        for key in points:
            print(key,points[key])

---

下次试着把你对这个问题的尝试也贴出来。干杯

你在这里发布的是要求。您为这些要求编写了哪些代码？让我们看看你的工作和你的困境

Points scored after:  1
England 0
Poland 3
Italy 0
Sweeden 0
Spain 0
Belgium 0
Points scored after:  1
England 0
Poland 6
Italy 0
Sweeden 0
Spain 0
Belgium 0
Points scored after:  2
England 0
Poland 6
Italy 3
Sweeden 0
Spain 0
Belgium 0
Points scored after:  2
England 0
Poland 6
Italy 6
Sweeden 0
Spain 0
Belgium 0
Points scored after:  3
England 0
Poland 6
Italy 6
Sweeden 0
Spain 1
Belgium 1
Points scored after:  3
England 0
Poland 6
Italy 6
Sweeden 0
Spain 2
Belgium 2